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3 years ago

Solve for x: 3(x - 2) = -9

Mathematics

1 answer:

Airida [17]3 years ago

5 0

Answer:

X=-1

Step-by-step explanation:

3x-6=-9

3x=-9+6

3x=-3

x=-1

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Find all solutions of the equation in the interval [0, 2π). cotθ+ √3= 0

Ilia_Sergeevich [38]

Answer:

{5π/6, 11π/6}

Step-by-step explanation:

Since you have memorized the trig values of common angles, you know tan(π/6) = 1/√3, so cot(π/6) = √3.

The solution to this equation is ...

cot(θ) = -√3

so θ = -π/6 or, in the domain of interest, 11π/6. There is a corresponding quadrant II angle, 5π/6.

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3 years ago

Inside a toy truck, there is a gear that rotates to (3, −8) when the steering wheel is turned to the left. What is the sine valu

Marianna [84]

This is the the concept of trigonometry, to get the sine value of the the function given we shall proceed as follows;
Using Pythagorean theorem, the hypotenuse of the triangle will be found as follows;
The side length will be 8 units since the y-coordinate is -8
The side width will be 3 units since the x- coordinate is 3
c^2=a^2+b^2
c^2=(3)^2+(-8)^2
c^2=9+64
c^2=73
c=sqrt(73)

Therefore the sine value will be:
sin x=3/sqrt(73)
multiply both numerator and denominator by sqrt(73) we get:
sin x=(3√73)/73

Therefore the answer is A]

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3 years ago

Please answer this I REALLY REALLY REALLY NEED IT....

ziro4ka [17]

The answers to this questions would be:

1. A-> (1.5, 1.5) 5. A and B-> 7 units

2. B-> (-2, -1.5) 6. C and D-> 3 units

3. C-> (-3.5, 2) 7. B and D-> 1 unit

4. D-> (0.5, 0) 8. A and D-> 8 units

-------------------------------- WORD PROBLEMS------------------------------------------

9. 8 feet

10a. (-4, -1) 10b. (4, 1)

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4 years ago

Round 12,309,453 to the nearest million

Oliga [24]

Answer:

12,000,000

Step-by-step explanation:

7 0

3 years ago

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The graph of which function has a minimum located at (4, –3)?

valentinak56 [21]

Answer:

None of the options is the answer to the question

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

$f(x)=a(x-h)^{2}+k$

where

(h,k) is the vertex of the parabola

case A) we have

$f(x)=x^{2}+4x-11$

In this case the x-coordinate of the vertex will be negative

therefore

case A is not the solution

case B) we have

$f(x)=-2x^{2}+16x-35$

This case is a vertical parabola open downward (the vertex is a maximum)

The vertex is the point $(4,-3)$ <u>but is not a minimum</u>

see the attached figure

therefore

case B is not the solution

case C) we have

$f(x)=x^{2}-4x+5$

Convert into vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-5=x^{2}-4x$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-5+4=(x^{2}-4x+4)$

$f(x)-1=(x^{2}-4x+4)$

Rewrite as perfect squares

$f(x)-1=(x-2)^{2}$

$f(x)=(x-2)^{2}+1$ --------> vertex form

The vertex is the point $(2,1)$

therefore

case C is not the solution

case D) we have

$f(x)=2x^{2}-16x+35$

Convert into vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-35=2x^{2}-16x$

Factor the leading coefficient

$f(x)-35=2(x^{2}-8x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-35+32=2(x^{2}-8x+16)$

$f(x)-3=2(x^{2}-8x+16)$

Rewrite as perfect squares

$f(x)-3=2(x-4)^{2}$

$f(x)=2(x-4)^{2}+3$ --------> vertex form

The vertex is the point $(4,3)$

therefore

case D is not the solution

The answer to the question will be the function

$f(x)=2x^{2}-16x+29$

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4 years ago

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