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grigory [225]
2 years ago
5

My family uses 3 cartons of milk a day . how many cartons did we use in january

Mathematics
1 answer:
tangare [24]2 years ago
4 0

Answer:

93 cartons

Step-by-step explanation:

January-31

no of cartons-3 × 31=93

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For each figure, which placement of the axes shown would be the best to prove properties about the object?
xxMikexx [17]
Answers:
1) Rectangle: Right
2) Circle: Left
3) Equilateral Triangle: Right
4) Isosceles Triangle: Middle
5) Trapezoid: Middle
4 0
3 years ago
The doman of the function is?​
larisa [96]

Answer:

-9 <= x <= 7

Step-by-step explanation:

Domain is the x, or independent variable. you just need to find how far x goes. First, you go to the veeery left and then go to the veeeery right of the plotted graph. Those 2 numbers are your domain.

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3 years ago
Quadrilateral A'B'C'D is the image of quadrilateral ABCD under a translation.
Temka [501]

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8 0
2 years ago
Read 2 more answers
Emerson is making a punch that contains 60% grape juice and the rest lemon-lime soda. The punch has 2 liters of lemon-lime soda.
IrinaK [193]
A punch contains 60% of grape juice and the rest is lemon - lime soda ( 2 liters).
Part A:
An equation is:
0.6 x + 2 = x,
where x stays for the liters of punch.
Part B:
x - 0.6 x = 2
0.4 x = 2
x = 2 : 0.4
x = 5 liters
Grape juice = 5 - 2 = 3 liters.
Answer: There are 3 liters of grape juice in the punch.
8 0
3 years ago
A civil engineer is analyzing the compressive strength of concrete. Compressive strength is normally distributed with A random s
wel

Answer:

95%: (3278.354 ; 3270.083)

99% : (3221.646 ; 3278.354)

Step-by-step explanation:

Given :

Sample size, n = 12

Mean, xbar = 3250

Sample standard deviation = √1000

The 95% confidence interval :

Mean ± Margin of error

Margin of Error = Tcritical * s/√n

Tcritical at 0.05, df=12-1 = 11 ;

Tcritical at 95% = 2.20

Hence,

Margin of Error = (2.20 * √1000/√12) = 20.083

Confidence interval : 3250 ± 20.083

Lower boundary = 3250 - 20.083 = 3229.917

Upper boundary = 3250 + 20.083 = 3270.083

2.)

The 99% confidence interval :

Mean ± Margin of error

Margin of Error = Tcritical * s/√n

Tcritical at 0.01, df=12-1 = 11 ;

Tcritical at 99% = 3.106

Hence,

Margin of Error = (3.106 * √1000/√12) = 28.354

Confidence interval : 3250 ± 28.354

Lower boundary = 3250 - 28.354 = 3221.646

Upper boundary = 3250 + 28.354 = 3278.354

3 0
3 years ago
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