Yes or no?? math workk

Two cats face each other 6 feet apart. Craze-E Cat advances 4 feet while Scared-T Cat retreats 2 feet. What is the distance sepa

kow [346]

The answer is 6 feet

5 0

3 years ago

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Irene tiene una colección de 50 dvd de películas de 90 minutos de duración cada una .Si el precio de cada uno era de 11€ , ¿cuan

Rainbow [258]

To solve this problem you must apply the proccedure shown below:

1. She has a total of 50 DVDs of 90 minutes each one of them. The cost of each DVD was 11€.

2. Therefore, to calculate the total cost of the collection, you must multiply the cost of each DVD by the total number of them:

$total=(11)(50)=550$ €

3. To calculate the total minutes of the collection, you must multiply 90 minutes by the total number of DVDs:

$(90min)(50)=4500min$

Therefore, the answer is: 550€ and 4500 minutes.

3 0

3 years ago

Nanu borrowed a certain sum at the rate of 10 % p.a. If she paid compound interest Rs. 1,290 at the end of two years compounded

Leokris [45]

Answer:

whats your answer please give

5 0

2 years ago

If x – 10 is a factor of x2 – 8x – 20, what is the other factor?

Svetach [21]

Answer:

The other factor is $(x+2)$

Step-by-step explanation:

we know that

$(x-a)(x-b)=x^{2}-xb-xa+ab$

$(x-a)(x-b)=x^{2}-(a+b)x+ab$

In this problem we have

$x^{2} -8x-20$

and

$a=10$ -----> because is a factor

substitute and solve for b

$x^{2} -8x-20=x^{2}-(10+b)x+10b$

so

$8=10+b\\b=-2$

Verify in the second equation

$-20=10b$ -----> $-20=10(-2)$ -----> $-20=-20$ --> is ok

The other factor is $(x+2)$

3 0

2 years ago

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Find the second partial derivatives of the following functions

artcher [175]

(a) z = 3x ² - 4xy + 15y ²

has first-order partial derivatives

∂z/∂x = 6x - 4y

∂z/∂y = -4x + 30y

and thus second-order partial derivatives

∂²z/∂x ² = 6

∂²z/∂x∂y = -4

∂²z/∂y∂x = -4

∂²z/∂y ² = 30

where ∂²z/∂x∂y = ∂/∂x [∂z/∂y] and ∂²z/∂y∂x = ∂/∂y [∂z/∂x].

(b) z = 4x eʸ

∂z/∂x = 4eʸ

∂z/∂y = 4x eʸ

∂²z/∂x ² = 0

∂²z/∂x∂y = 4eʸ

∂²z/∂y∂x = 4eʸ

∂²z/∂y ² = 4x eʸ

(c) z = 6x ln(y)

∂z/∂x = 6 ln(y)

∂z/∂y = 6x/y

∂²z/∂x ² = 0

∂²z/∂x∂y = 6/y

∂²z/∂y∂x = 6/y

∂²z/∂y ² = -6x/y ²

6 0

2 years ago