Whoever answers will get brainliest!! 9876.5

On Reese’s most recent phone bill bill, 80% of the minutes she used were calling her mother. If she talked to her mother for 348

dexar [7]

She used 278.4 minutes

5 0

3 years ago

Considering only the values of β for which sinβtanβsecβcotβ is defined, which of the following expressions is equivalent to sinβ

-Dominant- [34]

Answer:

$\tan(\beta)$

Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something. If you have options that you're building toward, aim toward one of them.

${\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}$ and ${\sec(\theta)}={\dfrac{1}{\cos(\theta)}$

Recall the following reciprocal identity:

$\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}$

So, the original expression can be written in terms of only sines and cosines:

$\sin(\beta)\tan(\beta)\sec(\beta)\cot(\beta)$

$\sin(\beta) * \dfrac{\sin(\beta) }{\cos(\beta) } * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) } {\sin(\beta) }$

$\sin(\beta) * \dfrac{\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} {\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}$

$\sin(\beta) *\dfrac{1 }{\cos(\beta) }$

$\dfrac{\sin(\beta)}{\cos(\beta) }$

Working toward one of the answers provided, this is the tangent function.

The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero. However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to $\tan(\beta)$ .

8 0

2 years ago

What is the polynomial function of lowest degree with lead coefficient 1 and roots 1 and 1 + i?

astra-53 [7]

x³ - 3x² + 4x - 2

complex roots occur in conjugate pairs

1 + i is a root then so is 1 - i

the factors of the polynomial are therefore

f(x) = (x - 1 )(x - (1 + i))(x - (1 - i))

= (x - 1 )(x² - 2x + 2 ) ( expand factors and simplify )

= x³ - 3x² + 4x - 2

4 0

3 years ago

Read 2 more answers

An engineering firm designs a custom hexagonal screw for a computer board. A sketch of the top of the screw is below. To the nea

Sphinxa [80]

The area of the screw head is 93.5m².

<h3>How to calculate the area?</h3>

The area of the hexagon can be illustrated based on the formula:

A = 3✓3/2 × a²

Base = 12.

Height = 3.

Area of each triangle = 0.5 × 12 × 3 = 18

Area of the rectangle = 12 × 6 = 72

Therefore the area of the screw head will be:

= 3√3/2 × 72

= 93.5m²

Learn more about area on:

brainly.com/question/25292087

#SPJ1

8 0

2 years ago

7 is less than or equal to 0.5v + 10

Strike441 [17]

X is less than or equal to -1.5

3 0

3 years ago

Whoever answers will get brainliest!! 9876.5 - 643.99 =?