0.3r/0.3=2.1/0.3
r=2.1/0.3
r=7
In private correspondence with the author of the question, it was determined
that 'y' is the variable of integration.
Therefore, 'a' is a constant for purposes of this integration, and that whole
'a' business can be taken outside the integral.
Integral [a/(1-ay) dy] = a/(1-a) integral [dy/y] = a ln(y)/(1-a) + C
Answer:
yes
Step-by-step explanation:
They both are 0.6 in decimal form
Answer:
1.2 is your answer have a nice day
Step-by-step explanation: