Draw a circuit with a 12-volt battery, a 100 ohms resistor in series, and two resistors (each of value 200 ohms) in parallel. Wh
1 answer:
Answer:
200 Ω
Explanation:
Hi there!
Please see below for the circuit diagram.
<u>1) Find the total resistance of the resistors in parallel</u>
Total resistance in parallel equation:
Both the resistors measure 200 Ω. Plug these into the equation as R₁ and R₂:
Therefore, the total resistance of the resistors in parallel is 100 Ω.
<u>2) Find the total resistance of the circuit</u>
Now, to find the total resistance of the circuit, we must add the 100 Ω we just solved for and the 100 Ω for the other resistor placed in series:
100 Ω + 100 Ω = 200 Ω
Therefore, the total resistance of the circuit is 200 Ω.
I hope this helps!
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Answer:
C. 220.100.100.45 to 220.100.100.46
Explanation:
The Classless IP subnetting of 220.100.100.0 begins from the fourth octet of the IP address. To get 45 subnet mask, it uses 6 bits from the fourth octet, which approximately give 64 subnets, while the remaining 2 bits are used for host IP addressing.
The useable host IP addresses are gotten from the formula '-2', with n=2 bits.
useable host IP addresses = 2^2 - 2 = 2 addresses per subnet.
While the 12th subnet is 12 x 2^2 = 44.
This means that the 12th subnet mask starts with 220.100.100.44 (as the network address) and ends with 220.100.100.47 as broadcast IP address, while '.45' and '.46' are the assignable addresses of the subnet.