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statuscvo [17]
3 years ago
8

If one jar of jalapeños cost $2, how much will 7 jars cost?

Mathematics
1 answer:
hjlf3 years ago
3 0

Answer:

14 dollars

Step-by-step explanation:

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There are 12 boys in a math class. The total number of students s depends on the number of girls in the class g. write an equati
Pani-rosa [81]
12 + g = s
12 boys + g girls = s students
5 0
3 years ago
The sum of two numbers is 62 the smaller number is 6 less than the larer number what are the numbers
muminat
X= larger number
x-6= smaller number

x + (x - 6)= 62
combine like terms

2x - 6= 62
add 6 to both sides

2x= 68
divide both sides by 2

x= 34 larger number


SMALLER NUMBER
x - 6= 34 - 6= 28


ANSWER: The smaller number is 28 and the larger number is 34.

Hope this helps! :)
5 0
3 years ago
Solve for x.<br><br><br><br> 80<br> 22<br> 40<br> 12
kari74 [83]
Use the Pythagorean theorem to solve this problem. So, 81+x^2=1681. ( Pythagorean theorem: a^2+b^2=c^2). x^2=1600. x=40.
4 0
3 years ago
What is the distance between points M and N?
Free_Kalibri [48]

By using <em>triangle</em> properties and the law of the cosine twice, we find that the distance between points M and N is approximately 9.8 meters.

<h3>How to determine the distance between two points</h3>

In this problem we must determine the distance between two points that are part of a triangle and we can take advantage of properties of triangles to find it. First, we determine the measure of angle L by the law of the cosine:

\cos L = \frac{(19.6\,m)^{2}-(14.8\,m)^{2}-(21.4\,m)^{2}}{-2\cdot (14.8\,m)\cdot (21.4\,m)}

L ≈ 62.464°

Then, we get the distance between points M and N by the law of the cosine once again:

MN = \sqrt{(7.4\,m)^{2}+(10.7\,m)^{2}-2\cdot (7.4\,m)\cdot (10.7\,m)\cdot \cos 62.464^{\circ}}

MN ≈ 9.8 m

By using <em>triangle</em> properties and the law of the cosine twice, we find that the distance between points M and N is approximately 9.8 meters.

To learn more on triangles: brainly.com/question/2773823

#SPJ1

6 0
2 years ago
What is fixed perimeter
lesya [120]
Maximizing the Area of a rectangle. Drag the locators to vary the width of the rectangle and see the effect on its area. For a rectangle with a perimeter of 40, the height is always 20 minus the width. This allows you to reduce the formula for the area. I hope this helps you
6 0
3 years ago
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