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statuscvo [17]
3 years ago
8

If one jar of jalapeños cost $2, how much will 7 jars cost?

Mathematics
1 answer:
hjlf3 years ago
3 0

Answer:

14 dollars

Step-by-step explanation:

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What is the value of b<br> 2b + 8 − 5b + 3 = −13 + 8b − 5
Yuri [45]

Answer:

See below.

Step-by-step explanation:

2b + 8 − 5b + 3 = −13 + 8b − 5

Reorder like terms.

2b-5b+8+3=8b-13-5

Combine those like terms. Then solve.

-3b+11=8b-18

      -11       -11

-3b=8b-29

-8b -8b

-11b=-29

/-11    /-11

b=2.64

-hope it helps

3 0
2 years ago
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Write a linear function f with the values f (0) = 5 and f(2) = -3 please help
Gelneren [198K]

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f(x) = 2x - 5

Step-by-step explanation:

3 0
2 years ago
Someone can help?? ​
oee [108]

Answer:

Step-by-step explanation:

let  cos^{-1}x=t

cos t=x

when x=1,cos t=1=cos 0

t \rightarrow 0

\lim_{x \to 1} \frac{1-\sqrt{x}}{(cos ^{-1}x)^2 } \\= \lim_{t \to 0} \frac{1-\sqrt{cos~t}}{t^2} \times \frac{1+\sqrt{cos~t}}{1+\sqrt{cos ~t}} \\= \lim_{t \to 0} \frac{1-cos~t}{t^2(1+\sqrt{cos~t})}}  \\= \lim_{t \to 0 }\frac{2 sin^2~\frac{t}{2}}{t^2(1+\sqrt{cos~t})}} \\= 2\lim_{t \to 0 }(\frac{sin~t/2}{\frac{t}{2} })^2 \times \frac{1}{4} \times  \lim_{t \to 0 }\frac{1}{1+\sqrt{cos~t}} \\=\frac{2}4} \times 1^2 \times \frac{1}{1+\sqrt{cos~0}} \\=\frac{1}{2} \times \frac{1}{1+1} \\=\frac{1}{4}

4 0
3 years ago
Bob paid 17.50 for a box of cards and .35 each for 18 stamps. What was the total cost in dollars and cents of the box of cards a
alexgriva [62]
$23.80 for a box of cards and 18 stamps
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2 years ago
14/100 in simplest form
Readme [11.4K]
0.14. hope this helps
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3 years ago
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