The expression that has a value of 62.45 is the second answer choice 0.6245 × 10²
To determine the expression that has a value of 62.45 among the given answer choices, we will evaluate each of the answer choices.
- For the first answer choice - 0.006245 × 105 = 0.006245 × 10⁵
0.006245 × 10⁵ = 624.5
- For the second answer choice - 0.6245 × 102 = 0.6245 × 10²
0.6245 × 10² = 62.45
- For the third answer choice - 6.245 ÷ 101 = 6.245 ÷ 10¹
6.245 ÷ 10¹ = 0.6245
- For the fourth answer choice - 624.5 × 103 = 624.5 × 10³
624.5 × 10³ = 624500
From above, the second answer choice is the expression that has a value of 62.45
Hence, the expression that has a value of 62.45 is 0.6245 × 10²
Learn more here: brainly.com/question/17633165
<h3>
Answer:</h3>
By <em>100 times</em>.
Step-by-step explanation:
Each time something is in Scientific Notation, to every power of 10 something is multiplied by, it grows by 10 times.
By knowing that, if both equations use the same starting number, you can minus the notation section from the larger value, to find the answer.
10^6 - 10^4 = 10^2 ---> 100 times.
Hope that helps, :)
Answer:
Yes, an isosceles triangle is always 45 45 90 so its TRUE!!
Using complementary angles, it is found that F = 47º.
<h3>What are complementary angles?</h3>
Two angles are complementary if the sum of their measures is of 90º.
If two angles A and B are complementary, the sine of one angle is the cosine of the other.
In this problem, 43º and 47º are complementary, hence:
sin 43º = cos 47º, which means that F = 47º.
More can be learned about complementary angles at brainly.com/question/11161460
Answer: We can find out the missing statement with help of below explanation.
Step-by-step explanation:
We have a rectangle ABCD with diagonals AC and BD ( shown in given figure.)
We have to prove: Diagonals AC and BD bisect each other.
In triangles, AED and BEC.
( By alternative angle theorem)
( Because ABCD is a rectangle)
( By alternative angle theorem)
By ASA postulate,
By CPCTC, 
and 
⇒ BE= ED and CE=EA
By the definition of bisector, AC and BD bisect each other.
