Can I get help with this
1 answer:
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Answer:
Jogging 6th time.
Step-by-step explanation:
We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.
We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.
We know that an arithmetic sequence is in form , where,
= nth term of sequence,
= 1st term of sequence,
n = Number of terms in sequence,
d = Common difference.
Let us find common difference of our given sequence as:
Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.
Let us solve for n.
We can also write next terms of our sequence as:
Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.
Answer:
$ 0.8.
Step-by-step explanation:
1) if to assume, 'c' - price of the coffee and 'd' - price of the doughnuts, then
2) it is possible to write the equation 1 (when five MinB enter): 3d+5c=3.3;
3) it is possible to write the equation 2 (when three aliens entered): 4d+3c=2.75;
5) if c=0.45 and d=0.35, then Ag.Z. paid 0.35+0.45=$ 0.8.