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IRINA_888 [86]
3 years ago
10

Can I get help with this ​

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
8 0

Answer:

i cant awnser it when ist sideways

Step-by-step explanation:

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What is the equation of the line parallel to x = 7, passing through the point (-4, 1)? A. X = -4 B. X = 1 C. Y = -4 D. Y = 1
77julia77 [94]

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x=-4

Step-by-step explanation:

6 0
3 years ago
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Which symbol correctly compares the two measurementsone pound 16 oz ​
myrzilka [38]

Answer:

the = symbol

Step-by-step explanation:

there are 16 oz in a pound

7 0
2 years ago
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Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16
IrinaK [193]

Answer:

Jogging 6th time.

Step-by-step explanation:

We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.

We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.

We know that an arithmetic sequence is in form a_n=a_1+(n-1)d, where,

a_n = nth term of sequence,

a_1 = 1st term of sequence,

n =  Number of terms in sequence,

d = Common difference.

Let us find common difference of our given sequence as:

\frac{3}{8}-\frac{3}{16}\Rightarrow \frac{6}{16}-\frac{3}{16}=\frac{3}{16}

Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.

1

Let us solve for n.

1

1

1\cdot \frac{16}{3}

5.333

n>5.333

We can also write next terms of our sequence as:

\frac{3}{16},\frac{6}{16}, \frac{9}{16},\frac{12}{16},\frac{15}{16},\frac{18}{16}

Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.

7 0
3 years ago
Can someone please do my math edgnuity for me?
Fudgin [204]

Answer: i will just let me know what

Step-by-step explanation:

3 0
2 years ago
While on a stakeout protecting Earth from the the universe, Agent K observed five men in black enter a coffee shop and get three
taurus [48]

Answer:

$ 0.8.

Step-by-step explanation:

1) if to assume, 'c' - price of the coffee and 'd' - price of the doughnuts, then

2) it is possible to write the equation 1 (when five MinB enter): 3d+5c=3.3;

3) it is possible to write the equation 2 (when three aliens entered): 4d+3c=2.75;

4) \ \left \{ {{3d+5c=3.3} \atop {4d+3c=2.75}} \right. \ = > \ \left \{ {{c=0.45} \atop {d=0.35}} \right.

5) if c=0.45 and d=0.35, then Ag.Z. paid 0.35+0.45=$ 0.8.

3 0
1 year ago
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