Answer: D
Frequency = 587.32 Hz
Step-by-step explanation:
One octave above has a frequency of 2 × 146.83 Hz = 293.66Hz (D4). Two octaves above has afrequency of 2 × 293.66 Hz = 587.32 Hz (D5)
It will be A) 1/7 because using the rise over run meathod you get 1/7 and it will be possitive
Answer:
12.56
Step-by-step explanation:
C= 2 x 3.14 x 2
(the other 2 is half of the circumference)
Answer:
C
Step-by-step explanation:
Using calculator to evaluate
≈ 20.5191 → C
Solve for v by simplifying both sides of the equation, then isolating the variable.
v = -1
