Answer:
82
Step-by-step explanation:
-27 -50(-2) + (-3)^2
-27+100+9
73+9
82
Answer:
7/16
Approximately 0.44
Step by step explanation:
For the 1st student to arrive before 2nd student,
* the probability that he(1st student)to arrive during 3/4 hrs = 3/4
*Then he(1st student) will need to wait for 1/4 hrs
*The probability that he(1st student) arrive during the last 1/4 hrs = 1/4
*Then he(1st student) waits for average of 1/8 hrs (1/4 + 1/4)=1/8
*The total time he(1st student) wait = (3/4 ×1/4) +(1/4× 1/8) = 7/32
*For 1st and 2nd student to meet, the 2nd student need to arrive when 1st student is still arround, therefore the probability that 2nd student arrives when 1st student is arround = 7/32
*If 2nd student arrives before 1st student, the probability that they would meet is 7/32
* Adding both together 7/32 + 7/32 = 7/16
ANSWER = 0.4375
=0.44
