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saw5 [17]
3 years ago
14

20 POINTS An electrician charges a set fee for every house call and then charges an hourly rate depending on how long the job ta

kes. The total cost of the electrician's services can be determined using the equation C=65+60t, where t is the number of hours the electrician spends at the house working. What is the slope of the equation and what is its interpretation in the context of the problem?
Mathematics
2 answers:
sattari [20]3 years ago
8 0

Answer:

Slope- 60

represents: The slope of the function is 6060 which represents the hourly rate charged.

Step-by-step explanation:

I did it in delta math lol and i got it right.

tatuchka [14]3 years ago
5 0

Answer:

the \: slope \: is \to \boxed{60}

Step-by-step explanation:

if \to C=65+60t \\  C=60t + 65 \\ but \: the \: \boxed{ c - intercept} \: is \: in \: the \: form \to \\ c = mt + b \\ hence \to \\ 60t = mt \\ m =  \frac{60t}{t}  \\ m = 60 \\  the \: slope \: is \to \boxed{60}

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En ampliar o reducir una fotografía, obtenemos copias de la fotografía original, pero de medida diferente. Si la anchura del ori
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Answer:

La anchura será de:

6 cm

Step-by-step explanation:

El formato original corresponde al 100%

Si se reduce un 60% quiere decir que:

100 - 60 = 40%

la reducción queda al 40%

entonces, por regla de tres:

15cm es al 100%

A cm es al 40%

A = 15*40/100

A = 6cm

7 0
3 years ago
How many students in the marching band are girls
Hoochie [10]

Answer:

Hello,

If 7/10 boys represent 28 boys so, 3/10 girls ? how many girls ?

cross product

7/10 > 28

3/10 > ?

3/10*28/(7/10)=12

There are 12 girls


Step-by-step explanation:


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3 years ago
Find the value of d.
Elena-2011 [213]

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5 0
3 years ago
The antibiotic clarithromycin is eliminated from the body according to the formula A(t) = 500e−0.1386t, where A is the amount re
PolarNik [594]

Answer:

Time(t) = 11.61 hours (Rounded to two decimal place)

Step-by-step explanation:

Given: The antibiotic  clarithromycin is eliminated from the body according to the formula:

A(t) = 500e^{-0.1386t}                 ......[1]

where;

A - Amount remaining in the body(in milligram)

t - time in hours after the drug reaches peak concentration.

Given: Amount of drug in the body is reduced to 100 milligrams.

then,

Substitute the value of A = 100 milligrams in [1] we get;

100= 500e^{-0.1386t}

Divide both sides by 500 we get;

\frac{100}{500}=\frac{ 500e^{-0.1386t}}{500}

Simplify:

\frac{1}{5} = e^{-0.1386t}

Taking logarithm both sides with base e, then we have;

\log_e (\frac{1}{5})= \log_e (e^{-0.1386t})

\log_e (\frac{1}{5})=-0.1386t         [ Using \log_e e^a =a ]

or

\log_e (0.2)=-0.1386t

-1.6094379124341 = -0.1386t

 [using value of \log_e (0.2) = -1.6094379124341 ]

then;

t = \frac{-1.6094379124341}{-0.1386}

Simplify:

t ≈11.61 hours.

Therefore, the time 11.61 hours(Rounded two decimal place) will pass before the amount of drug in the body is reduced to 100 milligrams


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