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saw5 [17]
3 years ago
14

20 POINTS An electrician charges a set fee for every house call and then charges an hourly rate depending on how long the job ta

kes. The total cost of the electrician's services can be determined using the equation C=65+60t, where t is the number of hours the electrician spends at the house working. What is the slope of the equation and what is its interpretation in the context of the problem?
Mathematics
2 answers:
sattari [20]3 years ago
8 0

Answer:

Slope- 60

represents: The slope of the function is 6060 which represents the hourly rate charged.

Step-by-step explanation:

I did it in delta math lol and i got it right.

tatuchka [14]3 years ago
5 0

Answer:

the \: slope \: is \to \boxed{60}

Step-by-step explanation:

if \to C=65+60t \\  C=60t + 65 \\ but \: the \: \boxed{ c - intercept} \: is \: in \: the \: form \to \\ c = mt + b \\ hence \to \\ 60t = mt \\ m =  \frac{60t}{t}  \\ m = 60 \\  the \: slope \: is \to \boxed{60}

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Natalka [10]

Answer:

<u>The correct answer is A. 1/8</u>

Step-by-step explanation:

<u>Let's solve (1/3 * 9/16) / 1 1/2 = x</u>

(1/3 * 9/16) / 1 1/2 = x

9/48 / 1 1/2 = 9/48 * 2/3 = 18/144

18/144, we can simplify dividing by 18 at the numerator and the denominator, this way:

x = 18 ÷ 18/ 144 * 18 = 1/8

<u>The correct answer is A. 1/8</u>

4 0
3 years ago
Hello, may someone plz help me
fenix001 [56]

Answer:

Step-by-step explanation:

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3 years ago
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Blababa [14]
                             |
                             |__x_- 4___________              2x³/2x² =x
   2x² + 2x +3        | 2x³ - 6x² +7x +3
                            - (<span>2x³ +2x² +3x)
</span>                                      -8x² +4x  +3                -8x²/2x² = -4
                                    <span>-(-8x² -8x  -12)
</span>                                              12x +15

(x-4) + (12x +15)/(2x² + 2x +3) 
6 0
3 years ago
What is 3/2=9/10k im having troble lots rly
tigry1 [53]

Answer:

k=  5 over 3  =1.667

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    (3)/(2)-((9)/(10)*k)=0

simplify 9/10

 3      9

 — -  (—— • k)  = 0  

 2     10

simplify 3/2

 3    9k

 — -  ——  = 0  

 2    10

   Find the Least Common Multiple

     The left denominator is :       2  

     The right denominator is :       10

Least Common Multiple:

     10

Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M  

   Denote the Left Multiplier by  Left_M  

   Denote the Right Multiplier by  Right_M  

   Denote the Left Deniminator by  L_Deno  

   Denote the Right Multiplier by  R_Deno  

  Left_M = L.C.M / L_Deno = 5

  Right_M = L.C.M / R_Deno = 1

Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      3 • 5

  ——————————————————  =   —————

        L.C.M              10  

  R. Mult. • R. Num.      9k

  ——————————————————  =   ——

        L.C.M             10

Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3 • 5 - (9k)     15 - 9k

————————————  =  ———————

     10            10  

Pull out like factors :

  15 - 9k  =   -3 • (3k - 5)

-3 • (3k - 5)

 —————————————  = 0  

      10      

When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 -3•(3k-5)

 ————————— • 10 = 0 • 10

    10    

Now, on the left hand side, the  10  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  -3  •  (3k-5)  = 0

Solve :    -3   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solve  :    3k-5 = 0  

Add  5  to both sides of the equation :  

                     3k = 5

Divide both sides of the equation by 3:

                    k = 5/3 = 1.667

one solution was found

k = 5/3 = 1.667

hope it helps sry its so long

7 0
3 years ago
Please solve these questions with the equations. Will give 80 points and mark brainliest to the person with the answers.
I am Lyosha [343]

1]

8(x-7)=128 \ \ /:8\\\\x-7=16 \ \ /+7\\\\\huge\boxed{x=23}

2]

16=2(x+7) \ \ /:2\\\\x+7=8 \ \ /-7\\\\\huge\boxed{x=1}

3]

\frac{7y}{7}=20\\\\\huge\boxed{y=20}

4]

2x-1=9 \ \ /+1\\\\2x=10 \ \ /:2\\\\\huge\boxed{x=5}

5]

2(x-8)=20 \ \ /:2\\\\x-8=10 \ \ /+8\\\\\huge\boxed{x=18}

5 0
3 years ago
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