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hichkok12 [17]
3 years ago
11

Plzzzzz helpppp asapppppppppp

Mathematics
2 answers:
asambeis [7]3 years ago
8 0

i believe its option 2

Marianna [84]3 years ago
8 0

reflection about the y axis.

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Determine the y-intercept of the following equation. help pls​
suter [353]

Answer:

0,8

Step-by-step explanation:

(-x-2)(x-4)=y

To find the x-intercept, substitute in 0 for y and solve for x. To find y-intercept, substitiue in 0 for x and solve for y.

(-0-2)(0-4)=y

(-2)(-4)=8

y=8

0,8

7 0
3 years ago
Express the given product as a sum or difference containing only sines or cosines.
beks73 [17]

Answer:

sin(8x)

Step-by-step explanation:

assuming that you didn't mean to write it twice

4 0
3 years ago
Point HH is located at (4,-2)(4,−2) on the coordinate plane. Point HH is reflected over the yy-axis to create point H'H ′ . Poin
marin [14]

Answer: Coordinates of H  : (−4,2)

4 0
2 years ago
Please answer all please​
Firdavs [7]

Answer:

Step-by-step explanation:

The first parabola has vertex (-1, 0) and y-intercept (0, 1).

We plug these values into the given vertex form equation of a parabola:

y - k = a(x - h)^2 becomes

y - 0 = a(x + 1)^2

Next, we subst. the coordinates of the y-intercept (0, 1) into the above, obtaining:

1 = a(0 + 1)^2, and from this we know that a = 1.  Thus, the equation of the first parabola is

y = (x + 1)^2

Second parabola:  We follow essentially the same approach.  Identify the vertex and the two horizontal intercepts.  They are:

vertex:  (1, 4)

x-intercepts:  (-1, 0) and (3, 0)

Subbing these values into y - k = a(x - h)^2, we obtain:

                                            0 - 4 = a(3 - 1)^2, or

                                                -4 = a(2)².  This yields a = -1.

Then the desired equation of the parabola is

y - 4 = -(x - 1)^2

7 0
3 years ago
A university knows from historical data that 25% of students in an introductory statistics class withdraw before completing the
Vikki [24]

Answer:

13.4%

Step-by-step explanation:

Use binomial probability:

P = nCr p^r q^(n-r)

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1-p).

Here, n = 16, r = 2, p = 0.25, and q = 0.75.

P = ₁₆C₂ (0.25)² (0.75)¹⁶⁻²

P = 120 (0.25)² (0.75)¹⁴

P = 0.134

There is a 13.4% probability that exactly 2 students will withdraw.

8 0
3 years ago
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