Given that,
![f(x) = \sqrt{x-3}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Csqrt%7Bx-3%7D)
To find,
The domain of f(x).
Solution,
We have, ![f(x) = \sqrt{x-3}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Csqrt%7Bx-3%7D)
To find domain,
The term under the square root must be positive or null as follows :
![x-3\ge 0](https://tex.z-dn.net/?f=x-3%5Cge%200)
Adding 3 both sides
![x-3+3\ge 0+3\\\\x\ge 3](https://tex.z-dn.net/?f=x-3%2B3%5Cge%200%2B3%5C%5C%5C%5Cx%5Cge%203)
So, the domain is x-3>0
.
The coordinates are 68276528
Answer:
10.6
Step-by-step explanation:
13+10.6= is 23.6
Hope this helps
B. You can get this by factoring the bottom of the first expression and then cancelling the terms. Then multiply by the inverse of the second.