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aivan3 [116]
3 years ago
12

On a test of 80 problems, Bill got 75% of the problems correct

Mathematics
2 answers:
AysviL [449]3 years ago
8 0
The correct answer is c, 60!
PtichkaEL [24]3 years ago
5 0
The answer is c hope that helped
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For which value of 0 is 0=-1 ?
bagirrra123 [75]

Answer:

theta =  \frac{3}{2} \pi + 2k\pi

Step-by-step explanation:

+2*k*pi is for the periodicity (if you turn 360° you get back to the same point)

4 0
3 years ago
Find the value of the expression: a 8x^3 for x=-2;-1;0;3
dsp73

Simply replace each x with the given value of x.

<u>When x = -2:</u>

8(-2)^3\\8(-8)\\\\=-64

<u>When x = -1:</u>

8(-1)^3\\8(-1)\\\\=-8

<u>When x = 0:</u>

8(0)^3\\8(0)\\\\=0

<u>When x = 3:</u>

8(3)^3\\8(27)\\\\=216

OR you could use a graph for this, here is how the function is going to look:

3 0
3 years ago
A floor tile is 2ft wide . Convert the width to inches
lesya [120]

Answer: 24 inches

Step-by-step explanation:

First, remember that 1 ft is equal to 12 in

Then, if 1 ft = 12 in

1 = 12in/1ft

this means that we can write a constant:

C = 12in/1 in

and C = 1, then we can write the width 2ft as:

2ft = 2ft*C = 2ft*12in/1ft = 24in

7 0
3 years ago
A coat regularly cost $125 is put on sale for $75
Stels [109]
If a coat is regularly $125, and they mark it down to $75, we could figure out how much money was taken off by subtracting $75, from $125

$125 - $75 = $50

So the coats price was cut by $50.

Hope it helps
Please mark brainliest!
7 0
3 years ago
Answer this correctly for brainliest pls!!
Molodets [167]

A function that depicts depreciation can be represented as equations, graphs and tables.

<h3>The yearly value of each car for the first five years</h3>

The functions are given as:

V(t) =C(1 - r^t)

V(t) =C(1 - r)^t

Where:

C = 5895 --- the initial value of the car

r = 22% --- the rate of depreciation

For the first 5 years, the values of t = 1, 2, 3, 4 and 5

For the first function, we have:

V(1) =5895(1 - 22\%^1) = 4598.1

V(2) =5895(1 - 22\%^2) = 5609.7

V(3) =5895(1 - 22\%^3) = 5832.2

V(4) =5895(1 - 22\%^4) = 5881.2

V(5) =5895(1 - 22\%^5) = 5892.0

For the second function, we have

V(1) =5895(1 - 22\%)^1 = 4598.1

V(2) =5895(1 - 22\%)^2 = 3586.5

V(3) =5895(1 - 22\%)^3 = 2797.5

V(4) =5895(1 - 22\%)^4 =2182.0

V(5) =5895(1 - 22\%)^5 = 1702.0

So, the table of values is:

\left[\begin{array}{ccc}Years&Car\ 1&Car\ 2\\1&4598.1&4598.1\\2&5609.7&3586.5\\3&5832.2&2797.5\\4&5881.2&2182.0\\5&5892.0&1702.0\end{array}\right]

See attachment for the graphs of the two functions

<h3>Interpreting the graphs</h3>

The graph of car 1 increases up to C(t) = 5895, and then remains constant as the value of t increases while the graph of car 2 follows an exponential pattern.

This means that, the graph 2 that follows an exponential pattern is more realistic

<h3>The worth of the cars after 5 years</h3>

From the table, the worth of car 1 is $5892.0, while the worth of car 1 is $1702.0

Read more about graphs and functions at:

brainly.com/question/13473114

5 0
2 years ago
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