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Marianna [84]
3 years ago
14

eduardo works as an accountant for a consulting firm. he earns an annual salary of 68,090 and an annual bonus based of the firms

preformance. this year eduardo will earn a bonus of 3% of his annual salary , which is 2,042.70. what is eduardos annual gross pay
Mathematics
1 answer:
AURORKA [14]3 years ago
4 0

Answer:

70.132,70

Step-by-step explanation:

68.090,00

+ 2.042,70

_________

70.132,70

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Can u solve these 4 me?
Ber [7]

So for this:

(-1/3+-0.3/3+1) ^2

(-1/3-0.1+1)^2

(1-1.3/3)^2

(1-0.433333)^2

0.566667^2

Answer: 0.321111

0.32

8 0
3 years ago
Is the origin located at the intersection of the x - and y -axis
Nastasia [14]

yes it is because thats exactly where its located

4 0
3 years ago
According to an​ almanac, 70​% of adult smokers started smoking before turning 18 years old. ​(a) if 200 adult smokers are rando
Strike441 [17]

Solution: ​(a) if 200 adult smokers are randomly​ selected, how many would we expect to have started smoking before turning 18 years​ old?

Answer: It is expected that in a random sample of 200 adult smokers, 0.70 (200)=140 will have started smoking before turning 18.

​(b) would it be unusual to observe 160 smokers who started smoking before turning 18 years old in a random sample of 200 adult​ smokers? why?

Answer: Yes, it would be unusual to observe 160 smokers who started smoking before turning 18 years old in a random sample of 200 adult​ smokers, because 160 is greater than μ + 2σ

3 0
3 years ago
g a club of 12 people would like to choose a person for each office of president, a vice president, and a secretary. How many di
-Dominant- [34]

Answer:

220 possible ways

Step-by-step explanation:

Given

n = 12 --- people

r = 3 -- posts (President, Vice\ President\ and\ Secretary)

Required

Determine the number of selection

Since there is no condition attached, the number of selection is:

Selection = ^nC_r

Substitute values for n and r

Selection = ^{12}C_3

Apply combination formula

Selection = \frac{12!}{(12-3)!3!}

Selection = \frac{12!}{9!3!}

Selection = \frac{12*11*10*9!}{9!*3*2*1}

Selection = \frac{12*11*10}{6}

Selection = \frac{1320}{6}

Selection = 220

<em>Hence, there are 220 possible ways</em>

5 0
3 years ago
Daniel and Jack together sell 96 tickets to a raffle. Daniel sold 12 more tickets than his friend. How many raffle tickets each
Vlad1618 [11]

Answer:

Daniel sold 54 and Jack sold 42

Step-by-step explanation:

D = number of tickets that Daniel sold

J = number of tickets that Jack sold

D + J = 96

D = 12+ J

Substitute the second equation into the first equation

12 + J + J = 96

Combine like terms

12 + 2J = 96

Subtract 12 from each side

2J = 84

Divide by 2

J = 42

D = J+12

D = 54

Daniel sold 54 and Jack sold 42

7 0
3 years ago
Read 2 more answers
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