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2 years ago

12

Pls help ASAP i don’t have time!!!!!

1 answer:

Lesechka [4]2 years ago

6 0

Answer:

Step-by-step explanation:

Let the width be W.

14w=(8*10)

14w=80

The width of the frame needs to be at least 5.7 inches.

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Find the surface area of a cylinder with the following dimensions. Use 3. 14 for $. Round your answer to the nearest

kupik [55]

Answer:

b

Step-by-step explanation:

r=d/2=11.4/2=5.7

slant surface area=2πr*h=11.4×3.14×4.4=157.5024 cm^2

area of base and top=2(πr²)=2×3.14×(5.7)²=204.0372 cm²

total surface area=157.5024+204.0372=361.5396=361.5 sq. cm

7 0

2 years ago

Ahmad has $x. Abu has $5 more than Ahmad. Razak has twice as much as Abu. Together they have $175. What is the value of x?

Alisiya [41]

Abu X + 5

Razak 2x + 10

Ahmad X

Together 4x + 15

175 - 15 = 160

160 / 4 = 40

X = 40

7 0

2 years ago

Read 2 more answers

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$

= $(\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5$

= $(\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]$

= $(\frac{3}{4^4})[1+\frac{1}{16}]$

= $(\frac{3}{256})[\frac{17}{16}]$

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0

2 years ago

6) (after 2.3) Consider the infinite system of linear equations in two variables given by ax + by = 0 where (a, b) moves along t

Paraphin [41]

Answer:

Step-by-step explanation:

Given infinite system of linear equations is ax + by = 0

when (a,b) moves along unit circle in plane.

a) system having unique system (0, 0)

Since two of equation in thus system will be

$1.x+0.y=0\\x=0$

and

$0.x+1.y=0\\y=0$

It is clear that x = 0, y= 0 is the only solution

b) Linear independent solution in this system gives some set of solutions

$1.x+0.y=0\\\x=0$

and

$0.x+1.y=0\\y=0$

Vector form is

$\left[\begin{array}{ccc}1&0\\0&1\end{array}\right] =I$

c) for this equation if add 0x +0y = 0 to system , Nothing will change

Because [0,0] satisfies that equation

d) If one of the equation is ax + by = 0.00001

where 0.00001 is small positive number

so, the system will be inconsistent

Therefore, the system will have no solution.

6 0

3 years ago

A blimp can be seen flying at an altitude of 5500 feet above a motor speedway during a race. The slanted distance directly to th

Vladimir [108]

Answer:

The expression of h as function of x is h = $\sqrt{(d + 5500) (d - 5500)}$

Step-by-step explanation:

Given as :

The distance of blimp (AB) = 5500 feet

The slanted distance to the pagoda (BC) = d feet

The horizontal distance (AC) = h

Let the angle made between slanted distance and horizontal distance be Ф

So , cos Ф = $\frac{AC}{BC}$ = $\frac{h}{d}$

And sin Ф = $\frac{AB}{BC}$ = $\frac{5500}{d}$

∵, cos²Ф = 1 - sin²Ф

So, $(\frac{h}{d})^{2}$ = $1 - (\frac{5500}{d})^{2}$

Or, $(\frac{h}{d})^{2}$ = $(\frac{d^{2}- 5500^{2}}{d^{2}})$

Or, h² = d² - 5500²

∴ h = $\sqrt{d^{2}- 5500^{2}}$

Or, h = $\sqrt{(d + 5500) (d - 5500)}$

Hence The expression of h as function of x is h = $\sqrt{(d + 5500) (d - 5500)}$ Answer

3 0

3 years ago