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Westkost [7]
3 years ago
8

Last winter, Tom earned $47.50 shoveling snow and $122 giving ice-skating lessons. During the summer, he earned twice as much by

doing yard work. Which expression shows how you could calculate the amount of money Tom earned during the summer?
Mathematics
1 answer:
siniylev [52]3 years ago
5 0
You would have to add 47.50 + 122 to get 169.5 dollars. to get the amount of money he made in the summer, you would have to multiply 169.5 by 2 which would equal 339 dollars. so he made 339 dollars over the summer :)
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Solve for x:<br> <img src="https://tex.z-dn.net/?f=x-2%28x-%5Cfrac%7B3%7D%7B2%7Dx%29%3D2%284-x%29%2B10" id="TexFormula1" title="
Arlecino [84]

Answer:

x = \frac{9}{2}

Step-by-step explanation:

x - 2 (x - \frac{3x}{2}) = 2 (4 - x) + 10

x − 2 × \frac{-x}{2} =2(4−x)+10

x−(−x)=2(4−x)+10

x+x=2(4−x)+10

2x=2(4−x)+10

2x=8−2x+10

2x=−2x+18

2x+2x=18

4x=18

x = \frac{18}{4}

x = \frac{9}{2}

7 0
3 years ago
Icon" to view the SpeechStream® loolbar article for
RUDIKE [14]

<u>Answer:</u>

\simeq 820 feet

<u>Step-by-step explanation:</u>

He has asked me to move the finish line 0.25 km forward

Now,

we know that

1 km = 0.621371 mile

⇒ 0.25 km = 0.25 \times 0.621371 mile  

                   = 0.25 \times 0.621371 \times 1760 \times 3 feet

(since 1760 yards = 1 mile and 3 feet = 1 yard)

                    = 820.20972 feet

                   \simeq 820 feet . (Answer)

8 0
3 years ago
THIS IS THE LAST ONE NUMBER 9
Cloud [144]

Answer:(d)

Step-by-step explanation:

Given

AB=AC

\therefore We can write

\angle ABC=\angle ACB\ \quad \text{[angles corresponding to equal sides are equal]}

\angle ABC=\angle BCA=\angle ACB=65^{\circ}

8 0
3 years ago
Three unit squares (1-by-1 squares) and two line segments connecting two pairs of vertices are shown.
nasty-shy [4]

Answer:

Step-by-step explanation:

I don't know if, just because I'm a high school math teacher, I way over-think things, but the method I used to come to the answer here is crazy and convoluted...but it works. Follow me here while I explain it.

I put that drawing you have there in a coordinate plane and made a point D at the end of the segment that begins with A; made a point E at the end of the segment that begins with B. Putting that into a coordinate plane with E at the origin gives A coordinates of (0, 2); B (1, 2); D (2, 1). We need to find the coordinates of C to use later. That's the first job.

When you put this into a coordinate plane, it allows you to write the equations of the segments AD and BE.

AD: y = -1/2x + 2

BE: y = 2x

If you set these equal to each other, you can see where the lines intersect (the coordiantes of this point) by solving for x and y.

-1/2x + 2 = 2x and

2.5x = 2 so

x = .8

And if x = .8, we can sub that into either equation to find y:

y = 2(.8) so

y = 1.6

So the coordinates of C are (.8, 1.6).

Now we can find the lengths of each of these segments AC and BC. We already know that the length of segment AB is 1.

Find the lengths of each of these segments using the coordinates for each in the distance formula. The lengths are as follows:

AC = .8944

BC = .4472

This allows me to use the Law of Cosines to find the measure of angle A.

Angle A = 26.56°

Now I can use the area formula for a triangle that says

A_{triangle}=\frac{1}{2}AB*ACsinA and

A=\frac{1}{2}(1)(.8944)sin26.56 so

A = .1999 units squared

8 0
3 years ago
Given square ABCD, what is the length of AD?
Orlov [11]

Answer:

AD=AB

Step-by-step explanation:

3x-5=x+1

It's a square

You solve for x then plug it back in

5 0
3 years ago
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