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2 years ago

(k + 3)by the power of 3

Mathematics

1 answer:

kolezko [41]2 years ago

7 0

Your answer is: 3k + 9

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Find the sum -6/3 - (-7/15)

Brums [2.3K]

Answer:

-1 $\frac{8}{15}$

Step-by-step explanation:

That's the answer I think

8 0

3 years ago

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Waht is 2t2 math fir math clas

Lelechka [254]

2+2 is 4 LOL you just gotta add 1+1+1+1

4 0

3 years ago

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The midpoint of (-4,15) and (22,3)

ahrayia [7]

Answer:

(9, 9)

Step-by-step explanation:

midpoint of (-4,15) and (22,3)

$= \bigg( \frac{ - 4 + 22}{2}, \: \: \frac{15 + 3}{2} \bigg) \\ \\ = \bigg( \frac{18}{2}, \: \: \frac{18}{2} \bigg) \\ \\ = ( 9, \: \: 9) \\ \\$

8 0

3 years ago

I need help please .

levacccp [35]

Answer:

Step-by-step explanation:

You know that anything to the zeroeth power is 1, so the equation is now

-7 * 1, or -7.

7 0

3 years ago

1) Solve the following system of equations algebraically. Give your solution as two

Bad White [126]

For this case we have the following system of equations:

$y = x ^ 2 + 7x + 12\\y = 2x + 8$

Equating both equations we have:

$x ^ 2 + 7x + 12 = 2x + 8\\x ^ 2 + 7x-2x + 12-8 = 0\\x ^ 2 + 5x + 4 = 0$

We must find the solutions, for this we factor. We look for two numbers that, when multiplied, result in 4 and when added, result in 5. These numbers are 4 and 1:

$4 + 1 = 5\\4 * 1 = 4$

Then, the factorized equation is of the form:

$(x + 4) (x + 1) = 0$

Thus, the solutions are:

$x_ {1} = - 4\\x_ {2} = - 1$

We look for solutions for the variable "y":

$y_ {1} = 2 (-4) + 8 = -8 + 8 = 0\\y_ {2} = 2 (-1) + 8 = -2 + 8 = 6$

Thus, the system solutions are given by: $(x_ {1}, y_ {1}): (- 4,0)\\(x_ {2}, y_ {2}): (- 1,6)$

ANswer:

$(x_ {1}, y_ {1}): (- 4,0)\\(x_ {2}, y_ {2}): (- 1,6)$

8 0

3 years ago

(k + 3)by the power of 3​

(k + 3)by the power of 3