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dangina [55]
2 years ago
10

(k + 3)by the power of 3​

Mathematics
1 answer:
kolezko [41]2 years ago
7 0
Your answer is: 3k + 9
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Is the open sentence 3z=2z+5 true or false when z=5?<br><br> A. True<br> B. False
inna [77]
Hey there! 

If z = 5 

we replace "z" with "5" 

So, let's test out the problem to see if it is true or false

Problem becomes: 3(5) = 2(5) + 5

Let's work this out

3(5) = 15

Problem becomes: 15 = 2(5) + 5

2(5) = 10

Problem becomes: 15 = 10 + 5

10 + 5 = 15

So, therefore it looks like this statement/ sentence is True!

~MeIsKaitlyn:)

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What is the value of x?<br> sin 55' = COS 3<br> Fnter your answer in the box
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How can you use transformations to graph this<br> function?<br> y=3•7-x+2<br> Explain your steps.
ElenaW [278]

The last two easy transformations involve flipping functions upside down (flipping them around the x-axis), and mirroring them in the y-axis.

The first, flipping upside down, is found by taking the negative of the original function; that is, the rule for this transformation is –f (x).

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2 years ago
What fraction is equal to 65%?
umka21 [38]

Answer:

65/100

Divide is by 100.

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As you can see I keep getting questions wrong.... Can you answer the last question?
aivan3 [116]

Answer:

  y = 0

Step-by-step explanation:

It is always a good idea to look at the question and make some observations about it. Here, you might observe ...

  • all of the bases are powers of 3: 243 = 3^5; 9 = 3^2
  • y is a factor of every exponent

The latter observation is important, because it means that when y=0, every exponential expression has a value of 1. Hence y = 0 is a solution.

__

To solve the equation, you can write it in terms of powers of 3.

  (3^5)^(-y) = (3^-5)^(3y)·(3^2)^(-2y)

  3^(-5y) = 3^(-15y)·3^(-4y)

  3^(-5y) = 3^(-19y)

  -5y = -19y . . . . . . . . equating exponents; equivalent to taking log base 3

  14y = 0 . . . . . . . . . . add 19y

  y = 0 . . . . . . . . . . . one solution

______

The rules of exponents we used are ...

  (a^b)(a^c) = a^(b+c)

  (a^b)^c = a^(bc)

  1/a^b = a^-b

4 0
3 years ago
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