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Hatshy [7]
3 years ago
8

The first four terms of a sequence are shown below. 2, 9, 40.5, 182.25 . . . What is the next number in the sequence?

Mathematics
1 answer:
Law Incorporation [45]3 years ago
5 0

Answer:

it is 820.125

Step-by-step explanation:

divide the second term by the first term to find what the multiple is.

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95% of what number is 19?
Setler79 [48]
95% of 20 is 19

Convert your percentage into a decimal: 
\frac{95}{100} = 0.95

Divide 19 by your decimal:
19 \div 0.95 = 20
8 0
3 years ago
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If Fred’s age now is three times what it was 12 years ago, how old is Fred 12 years ago?
Nikitich [7]

Answer:

6

Step-by-step explanation:

12+x=3x

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2 years ago
A pair of parallel lines is cut by a transversal as shown in the figure. Match the angles with their corresponding angles.
garri49 [273]
D and H are corresponding
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Please help urgent fasttt
sergeinik [125]

Answer:

  • Perimeter= l1+l2+w3+w4
  • Where l1 and l2 are equal in magnitude
  • Alike w3 and l
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3 0
3 years ago
I WILL MARK BRAINLIEST A bicycle manufacturing company makes a particular type of bike. Each child bike requires 4 hours to buil
Alona [7]

Using a system of equations, it is found that since 20 child bikes and 6 adult bikes would require more testing than the allocated time, it is not possible to build this amount.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are:

  • Variable c: number of child bikes.
  • Variable a: number of adult bikes.

Each child bike requires 4 hours to build, as do each adult bike. The company has 100 hours of testing, hence:

4c + 4a = 100.

c + a = 25.

With 20 child bikes and 6 adult bikes in a week, we have that c = 20, a = 26, hence:

c + a = 26

20 child bikes and 6 adult bikes would require more testing than the allocated time, it is not possible to build this amount.

More can be learned about a system of equations at brainly.com/question/24342899

#SPJ1

4 0
2 years ago
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