3 years ago

Which relation is a direct variation that contains the ordered pair (2, 7)?

Mathematics

1 answer:

Burka [1]3 years ago

8 0

Answer:

Step-by-step explanation:

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Read 2 more answers

A circle is centered on point (-2,-1). The circle passes through the point (-7,-7). What is its radius?

gayaneshka [121]

Answer:

-The answer for the radius:

$\sqrt{61} = r$

Step-by-step explanation:

-The equation of a circle is:

$(x-h)^2+(y-k)^2=r^2$ (where the center is known as $(h,k)$ , the point is $(x,y)$ and the radius known as $r$ ).

-Use both the center (-2,-1) and the point (-7,-7) for the equation:

$(-7+2)^2+(-7+1)^2=r^2$

-Then, solve the equation to get the radius:

$(-7+2)^2+(-7+1)^2=r^2$

$(-5)^2+(-6)^2=r^2$

$25+36=r^2$

$61 = r^2$

$\sqrt{61} = \sqrt{r^2}$

$\sqrt{61} =r$

So, therefore the radius is $\sqrt{61}$ .

6 0

3 years ago

AB:BD = 3:4 <br><br> AC:CD = 3:2 <br><br> Work out AB:BC:CD

Papessa [141]

Answer:

15:6:14

Step-by-step explanation:

AB:BD is split into a total of 3+4=7 parts.

AC:CD is split into a total of 3+2=5 parts.

So, if the two ratios are put on a number line together with the points A, B, C, and D, the number line would be split into a total of 35 parts (the LCM of 7 and 5).

AB would be (3/7)*35=15.

CD would be (2/5)*35=14

BC would be 35-(15+14)=6

So, the ratio is 15:6:14.

5 0

3 years ago