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wariber [46]
3 years ago
13

Explain when a relation is also a function

Mathematics
1 answer:
nordsb [41]3 years ago
4 0

Answer:

A relation is a function if the x-values map to only one y-value. In other words, if a relation is one-to-one or many-to-one it is a function.

Step-by-step explanation:

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Joy drank 2 3 liter of water Monday before going jogging. She drank 5 7 liter of water after her jog. How much water did Joy dri
Alexxandr [17]

Answer: 1 ⁸/₂₁ litres

Step-by-step explanation:

First find a common multiple to enable you add them up:

= 21

21 will be the denominator.

Multiply each numerator by the number you get when you divide 21 by the denominator.

= 21/3 = 7

= 7 * 2 = 14

= 21/7 = 3

= 3 * 5

= 15

= \frac{14 + 15}{21} \\\\= \frac{29}{21}

= 1\frac{8}{21} litres

8 0
3 years ago
Help me give thanks comment and brainliest
horrorfan [7]

Answer:

2 Ounces

Step-by-step explanation:

4 0
3 years ago
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A particle travels along the x-axis such that its velocity is given by v(t) = (t^0.7 + 4t) cos (t^2). What is the average accele
Airida [17]

It's not clear to me what the given interval is supposed to be, so I'll use a generic one, [a, b] with a < b.

The average acceleration of the particle over this interval is given by the average rate of change of v(t),

a_{\rm ave} = \dfrac{v(b) - v(a)}{b - a} = \boxed{\dfrac{(b^{0.7}+4b)\cos(b^2) - (a^{0.7}+4a)\cos(a^2)}{b - a}}

8 0
3 years ago
What type(s) of symmetry does the figure have? (Check all that apply.)
monitta

2 Answers:  A) line symmetry and B) rotational symmetry

=====================================================

Explanation:

We have line symmetry because we can draw a vertical line down the center, and this is a mirror line. One half folds over the vertical line to match up with the other half. There are other lines of symmetry as well.

We also have rotational symmetry because we can rotate the figure some amount of degrees and have it line up with its original image. The before and after will be identical. This applies to any regular polygon.

8 0
3 years ago
Value of complex number i^7+1/i^4​
Vera_Pavlovna [14]

i^7 + \dfrac 1{i^4}\\\\=i^2 \cdot i^2 \cdot i^2  \cdot i + \dfrac 1{i^2 \cdot i^2}\\\\=(-1)(-1)(-1)i + \dfrac 1{(-1)(-1)} ~~~;[ i^2 = -1] \\\\\ = (-1)^3 i+ \dfrac 1{(-1)^2} \\\\=-i+1

7 0
3 years ago
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