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Studentka2010 [4]
3 years ago
5

A trail mix is made up of peanuts that cost p dollars per pound and dried fruit that costs d dollars per pound. A blend of 1/2 p

ound of peanuts and 3/4 pound of dried fruit costs $6.50. A blend of 3/4 pound of peanuts and 1/4 pound of dried fruit costs $4.50. Which matrix equation can be used to solve for the cost of 1 pound of peanuts and the cost of 1 pound of dried fruit?
Mathematics
2 answers:
insens350 [35]3 years ago
7 0

Answer:

A

Step-by-step explanation:

(1/2 3/4

3/4 1/4)      (P/D) = (6.50

                              4.50)

Cerrena [4.2K]3 years ago
4 0
P is the cost of a pound of peanuts and F is the cost of a pound of dried fruit
0.5p+0.75f=6.5
0.75p+0.25f=4.5

Rearrange
0.5p=-0.75f+6.5

Simplify
P=-1.25f+13

Substitute
0.75(-1.25f+13)+0.25f=4.5

simplify
-0.9375f+9.75+0.25f=4.5
<span>-0.6875f+9.75=4.5
</span>-0.6875f=-5.25
f=7.636364

Round
F=$<span>7.64 per pound
</span>
Plug in
0.75p+0.25(7.64)=4.5

Simplify
0.75p+<span>1.91=4.5
0.75p=</span><span>2.59
</span>p=3.453333

Round
P=$3.45 per pound of peanuts

Final
P=$3.45 per pound of peanuts
F=$7.64 per pound of dried fruit
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5 0
3 years ago
If a spinner for a game is spun once, there is a 25% chance it will land on
bonufazy [111]

Answer:

Pr = 0.6

Step-by-step explanation:

Given

Let

O \to Orange

So:

P(O) = 25\% --- probability of O

n=2 --- Number of spin

Using the complement rule, the probability that a spin will not land on orange is:

P(O') = 1 - P(O)

P(O') = 1 - 25\%

Express as decimal

P(O') = 1 - 0.25

P(O') = 0.75

On two spins, the probability that it will not land on orange is:

Pr = P(O') * P(O')

So, we have:

Pr = 0.75* 0.75

Pr = 0.5625

<em></em>Pr = 0.6<em> --- approximated</em>

6 0
3 years ago
The graph shown here is the graph of which of the following rational
IrinaK [193]

Answer:

Option (B)

Step-by-step explanation:

From the graph attached,

Vertical asymptotes of the function are x = -2, 5

Horizontal asymptote is y = 0

Now we take each option,

Option (A),

F(x) = \frac{x(x-5)}{(x+2)}

No horizontal asymptote

Vertical asymptote : x = -2

Option (B),

F(x) = \frac{x}{(x+2)(x-5)}

Horizontal asymptotes : y = 0

Vertical asymptotes : x = 5, -2  

Option (C),

F(x) = \frac{(x+2)(x-5)}{x}

Vertical asymptote : x = 0

No horizontal asymptote.

Therefore, Function given in Option (B) matches the asymptotes given in the graph.

Option (B) represents the graph.

7 0
4 years ago
2 Determine whether the table represents a linear relationship. If so, state the slope of
yarga [219]

Answer:

  • Tables A and B represent linear relationship

-------------------------

<h3>Table A</h3>
  • x = 2, 3, 4, 5                  Difference is 1
  • y = 14, 21, 28, 35           Difference is 7
  • This is linear and the slope is 7

<h3>Table B</h3>
  • x = -2, -1, 0, 1                  Difference is 1
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<h3>Table C</h3>
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6 0
2 years ago
What is the slope of the tangent line to the parametric curve x = t^2 + 2t, y = t^2 + 1 at t = 1? (4 points)
ryzh [129]

ANSWER

\frac{1}{2}

EXPLANATION

The given parametric curve has equation:

x =  {t}^{2}  + 2t

and

y =  {t}^{2}  + 1

Let us differentiate each equationtion with respect to t.

\frac{dx}{dt}  = 2t + 2

and

\frac{dy}{dt}  = 2t

The slope function is given by:

\frac{dy}{dx}  =  \frac{ \frac{dy}{dt} }{ \frac{dx}{dt} }

This implies that:

\frac{dy}{dx}  =  \frac{2t}{2t + 2}

At t=1,

\frac{dy}{dx}  =  \frac{2(1)}{2(1)+ 2}

\frac{dy}{dx}  =  \frac{2}{4}

\frac{dy}{dx}  =  \frac{1}{2}

The correct choice is A.

7 0
4 years ago
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