How do you find the perimeter of shaded regions?

Mathematics

1 answer:

xxTIMURxx [149]2 years ago

6 0

Answer:

Perimetre of the rencatngel Perimetre of the circle and substrac the.

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Find the midpoint from (-2,-2) to (6,6)

timama [110]

(2,2)

(x1+x2)/2, (y1-y2)/2
(-2+6)/2=(2)
(-2+6)/2=2

4 0

2 years ago

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Jim decides to start a small nonprofit business of renting out motor scooters to help out his area residents. He puts in his own

Otrada [13]

First, find the expected number of scooters rented per month:

As the data is symmetrical, E(X) (the expected value) is the middle value. So, on average, 2.5 scooters should be taken per month.

His total costs were 5 * 3000 = $15,000

So, to break even, he needs to make $15,000.

He will be selling for 5 years, or 60 months.

As a result, he needs to make 15000/60 = $250/month

As he is selling 2.5 scooters on average, he needs to rent each for:

$250/2.5 = <u>$100/month</u>

8 0

3 years ago

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How do u do this.I need major help on it

Tpy6a [65]

Look for what 'y' is when t = 1 and t = 2. Go to the graph, look at 1 on the bottom axis and go up till you find the point, then go all the way to the left to see what the y-value is, in this case it should be 1200. If you do the same with t = 2, you will get 2400. So our two ordered pairs are:

(1, 1200), (2, 2400)

We can find the slope of these two points by plugging them into the slope formula:

$\sf m=\dfrac{y_2-y_1}{x_2-x_1}$

For points in the form of (x1, y1), (x2, y2). Plug in what we know:

$\sf m=\dfrac{2400-1200}{2-1}$

Subtract:

$\sf m=\dfrac{1200}{1}$

Divide:

$\sf m=1200$

This is the slope, so we can write the equation:

$\boxed{\sf y=1200t}$