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3 years ago

What are the potential solutions to the equation?

Mathematics

1 answer:

vekshin13 years ago

3 0

If this is the full question; What are the potential solutions to the equation below? 2In(x+3)=0

then the answer is; 2ln(x + 3) = 0

ln[(x + 3)²] = 0

(x + 3)² = 1

x + 3 = ±√1

x + 3 = ±1

x = 1 - 3, -1 - 3

x = -2, -1 - 3

x = -2, -4

when checking solution; x = -4 in the original equation does not hold true. so you drop x = -4 from the solution set.

therefore;

x = -2

hope this helps, God bless!

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Find the surface area of a box measuring 4 inches long 3 inches wide and 6 inches tall

Rufina [12.5K]

4*3

12*6

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3 years ago

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Iteru [2.4K]

Answer:

-5/4

Step-by-step explanation:

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3 0

2 years ago

1 Point

I am Lyosha [343]

Option C

The ratio for the volumes of two similar cylinders is 8 : 27

<h3><u>Solution:</u></h3>

Let there are two cylinder of heights "h" and "H"

Also radius to be "r" and "R"

$\text { Volume of a cylinder }=\pi r^{2} h$

Where π = 3.14 , r is the radius and h is the height

Now the ratio of their heights and radii is 2:3 .i.e

$\frac{\mathrm{r}}{R}=\frac{\mathrm{h}}{H}=\frac{2}{3}$

<em><u>Ratio for the volumes of two cylinders</u></em>

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{\pi r^{2} h}{\pi R^{2} H}$

Cancelling the common terms, we get

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{\mathrm{r}}{R}\right)^{2} \times\left(\frac{\mathrm{h}}{\mathrm{H}}\right)$

Substituting we get,

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{2}{3}\right)^{2} \times\left(\frac{2}{3}\right)$

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{2 \times 2 \times 2}{3 \times 3 \times 3}$

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{8}{27}$

Hence, the ratio of volume of two cylinders is 8 : 27

7 0

3 years ago

If AD=6 and AB=24, find AC

ruslelena [56]

When a perpendicular is dropped from the right-angle (C) to the opposite side AB, the metric relations apply:
BD*BA=a^2 ..........................(1)
AD*AB=b^2...........................(2)
BD*DA=DC^2........................(3)

Given AD=6, AB=24, using metric relation (2) above, we have
b^2=6*24=144
=>
b=sqrt(144)=12

By the way, we conclude that this is a 30-60-90 triangle because b/AB=(1/2)=sin(B) => B=30 degrees.

Answer: b=12

6 0

3 years ago

suppose andrew slept for eight hours one night. Ten percent of his sleep hours were before mignight. What.time did andrew go to

m_a_m_a [10]

Answer: 11:12 PM.
explanation:
- 10% of 8 is 0.8. (10% is 0.1, and you multiply this by 8)
- multiply 0.8 by 60 so you can get the number of minutes before midnight (this is 48).
- 48 minutes before midnight is 11:12.

6 0

3 years ago