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dem82 [27]
3 years ago
15

W (-4 + z) = mz + 17

Mathematics
1 answer:
Elan Coil [88]3 years ago
3 0
I think that is the answer

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WILL MARK BRAINLIEST AND THANK YOU!!! PLEASE HELP!!
Nadya [2.5K]

Answer:

426.9 Km²

Step-by-step explanation:

The shaded area is the area of the triangle subtract the area of the circle.

Area of triangle = 0.5 bh ( b is the base and h the perpendicular height )

Here b = 40 and h = 27, thus

Area = 0.5 × 40 × 27 = 20 × 27 = 540 Km²

Area of circle = πr² ← r is the radius

Here the diameter is 12, thus radius = 12 ÷ 2 = 6

Area = π × 6² = 36π ≈ 113.1 Km²

Shaded area = 540 - 113.1 = 426.9 Km²

6 0
3 years ago
Write the equation of a line that is parallel to y = -x + 7
Gnoma [55]

Answer:

y= -x-3

Step-by-step explanation:

A line is parallel to another line if their slope is the same. In this case the slope is -1 (-x is basically -1x). So far we have y=-x+b (We dont know what b is yet). next we can insert the coordinate back into the equation y=-x+b where 1 is the y and -4 is the x.

We get...

y= -x+b

1= -(-4)+b

1=4+b

b=-3

Our final equation is y=-x-3

Hope this helped

4 0
3 years ago
The converse of the perpendicular bisector theorem states,
Savatey [412]
"any point equally distant from the endpoints of a segment lies on the perpendicular bisector of the segment".
8 0
3 years ago
Find the missing value of X and Y.
Aneli [31]

Answer:

x = y = \sqrt{45}

Step-by-step explanation:

x^{2} + y^{2} = 30^{2}  \\x = y \\90 = \sqrt{45} +  \sqrt{45} \\\\ = 90

7 0
3 years ago
Find the sum of the A.P:8,-3,-2,-7,-12....up to n terms​
Ira Lisetskai [31]

Answer:

\frac{21n}{2} -\frac{5n^{2} }{2}

Step-by-step explanation:

  • given ap series : 8,3,-2,-7,-12....up to n terms​

[the second term should be +3 or else it wont form AP series]

first term in the series: 8

common difference : 3-8 = -5

total terms : n

  • the formula for sum of n terms in an ap = \frac{n}{2} [2a+(n-1)d]

a: first term

d: common difference

n : total terms

  • by substituting value in the above formula,
  • sum of the A.P: \frac{n}{2} [2(8)+(n-1)-5]

\frac{n}{2} [16+(n-1)(-5)]

\frac{n}{2} [16+(n-1)(-5)]

\frac{n}{2} [16+-5n+5]

\frac{n}{2} [21+-5n]

=\frac{21n}{2} -\frac{5n^{2} }{2}

6 0
4 years ago
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