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2 years ago

An outline of the school. The measurements are 48 yards, 50 yards, 9 yards, 30 yards, 30 yards, 30 yards, 9 yards, 50 yards.

Mathematics

2 answers:

valentina_108 [34]2 years ago

8 0

Answer:

Step-by-step explanation:

Perimeter equals the lengths of each side or edge added together

The perimeter of a square is P = 4 × side all four sides ar the same length

The perimeter of a rectangle is P = 2×L + 2×W

Perimeter of a circle is P = π × r

The perimeter here is a random polygon, but still just add up all sides to get your answer.

P = 47 + 50 + 9 + 30 + 30 + 30 + 9 +50

= 47 + 2×50 + 2×9 + 3×30

= 47 + 100 + 18 + 90

= 190 + 65

P = 255 yards I assume there is a typo somewhere in the question

Lelechka [254]2 years ago

3 0

Answer:

48 yards!

Step-by-step explanation:

its correct on edge!

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Find the x- and y-intercepts of the line x - 3y= -9

forsale [732]

Answer:

Step-by-step explanation:

To find the intercepts, that is where the line crosses the x and y axes

• Let x = 0, in the equation for y-intercept

• Let y = 0, in the equation for x- intercept

x = 0 : - 3y = - 9 ⇒ y = 3 ⇒ (0, 3) ← y- intercept

y = 0 : x = - 9 ⇒ (- 9, 0 )← x- intercept

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2 years ago

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Because of their connection with secant lines, tangents, and instantaneous rates, limits of the form ModifyingBelow lim With h

Gre4nikov [31]

Answer:

$\dfrac{1}{2\sqrt{x}}$

Step-by-step explanation:

$f(x) = \sqrt{x} = x^{\frac{1}{2}}$

$f(x+h) = \sqrt{x+h} = (x+h)^{\frac{1}{2}}$

We use binomial expansion for $(x+h)^{\frac{1}{2}}$

This can be rewritten as

$[x(1+\dfrac{h}{x})]^{\frac{1}{2}}$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}$

From the expansion

$(1+x)^n=1+nx+\dfrac{n(n-1)}{2!}+\ldots$

Setting $x=\dfrac{h}{x}$ and $n=\frac{1}{2}$ ,

$(1+\dfrac{h}{x})^{\frac{1}{2}}=1+(\dfrac{h}{x})(\dfrac{1}{2})+\dfrac{\frac{1}{2}(1-\frac{1}{2})}{2!}(\dfrac{h}{x})^2+\tldots$

$=1+\dfrac{h}{2x}-\dfrac{h^2}{8x^2}+\ldots$

Multiplying by $x^{\frac{1}{2}}$ ,

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}=x^{\frac{1}{2}}+\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}=\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$\dfrac{x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}}{h}=\dfrac{1}{2x^{\frac{1}{2}}}-\dfrac{h}{8x^{\frac{3}{2}}}+\ldots$

The limit of this as $h\to 0$ is

$\lim_{h\to0} \dfrac{f(x+h)-f(x)}{h}=\dfrac{1}{2x^{\frac{1}{2}}}=\dfrac{1}{2\sqrt{x}}$ (since all the other terms involve $h$ and vanish to 0.)

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GalinKa [24]

Answer:

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Step-by-step explanation:

Range is the greatest number of the set (7) subtracted by the smallest number of the set(1).

Mode is the most repeated number of the set(2).

<em>Hope this was helpful:)</em>

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