The largest consecutive integers whose sum is less than 46 are x= 21 and x+1=22
Step-by-step explanation:
Let the integers be:
x and x+1
The sum of these integers is less than 46

Solving and finding value of x:

So, the integers will be less than 22.5
The largest numbers are: 21 and 22
So, the largest consecutive integers whose sum is less than 46 are x= 21 and x+1=22
Keywords: Finding integers
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Answer:
is it to late now
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given

Required
The sample mean
This is calculated using:

So, we have:



Answer:
sqrt 24
Step-by-step explanation:
x^2-9=-15
x^2-9+9=-15+9
x^2=24
x=sqrt 24