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Rus_ich [418]
3 years ago
12

Describe how scientists would have to use to classify M.smithii into archea domain

Biology
2 answers:
Mazyrski [523]3 years ago
8 0

Answer(Explanation):

Methanobrevibacter smithii is the predominant archaeon in the microbiota of the human gut. M. smithii has a coccobacillus shape. It plays an important role in the efficient digestion of polysaccharides by consuming the end products of bacterial fermentation.

Archaea were initially classified as bacteria, receiving the name archaebacteria (in the Archaebacteria kingdom), but this term has fallen out of use. Archaeal cells have unique properties separating them from the other two domains, Bacteria and Eukaryota. Archaea are further divided into multiple recognized phyla.

stiks02 [169]3 years ago
6 0

Explanation:

Archaea were initially classified as bacteria, receiving the name archaebacteria (in the Archaebacteria kingdom), but this term has fallen out of use. Archaeal cells have unique properties separating them from the other two domains, Bacteria and Eukaryota. Archaea are further divided into multiple recognized phyla

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Explanation:

A geometric growth model is characterized by its finite growth rate, known as lambda. The size of the population after a unit of time has passed can be calculated using the last known size and lamba as:

N_{t+1} = \lambda * N_t

Starting from the initial value of population, the next one will be calculated multiplying by 1.4, and the next one multiplying again by 1.4, thus we can define a function that relates the time passed in year to the size of the population:

N(t) = \lambda^{t} *N_0

Substituting our values we get the function that defines the growth of our poupulation:

N(t) = 1.4^{t} *10

Then, we just have to clear the t that gives a population of 500:

500 =  1.4^t*10, divide\ both\ sides\ by\ 10\\50 = 1.4^t, apply\ log_{1.4}(x)\ to\ both\ sides\\log_{1.4}(50)=t\\11.63=t

Thus, at 12 years, the population will be greater than 500.

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3 years ago
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