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a_sh-v [17]
3 years ago
13

Someone help me?.......

Mathematics
1 answer:
vesna_86 [32]3 years ago
5 0

Answer:

i can help you of the math experience

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The box plots represent the ages of pennies in two 50-cent rolls. By looking at the plots, Beth says that the two means are abou
Neporo4naja [7]

Answer:

D)She may not be correct because means cannot be determined from Box plots.

Step-by-step explanation:

Box plot -Boxplot is a way to show the spread and centers of a data setboxplot and also called a box and whisker plot,

Box plot tells us about :

1) Mininmum value

2) 25th Percentile value

3)Median

4) 75th Percentile value

5)Maximum value

6) Interquartile Range

Now we are given that By looking at the plots, Beth says that the two means are about 5 years apart.

So,Option D is true

She may not be correct because means cannot be determined from Box plots.

6 0
3 years ago
Read 2 more answers
What is the first step to verify that the following identity is true?
umka2103 [35]

Step-by-step explanation:

this right ans according to your question

8 0
3 years ago
When you subtract one equation from the other what is the value of x
sweet [91]

Answer:

uh depends on the equations

6 0
3 years ago
Jena walk 6 miles karla walk 3 times as far as jena which expression shows how many karla walk
marta [7]

Answer:

y = 3x

y = 18

Step-by-step explanation:

Let :

Distance walked by Jena = x

Distance walked by Karla = y

x = 6

y = 3x ;

y = 3(6)

y = 18 miles

4 0
3 years ago
Assume the time required to complete a product is normally distributed with a mean 3.2 hours and standard deviation .4 hours. Ho
Alex787 [66]

Answer: 3.712 hours or more

Step-by-step explanation:

Let X be the random variable that denotes the time required to complete a product.

X is normally distributed.

X\sim N(\mu=3.2\text{ hours},\ \sigma=0.4\text{ hours} )

Let x be the times it takes to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

Then, P(\dfrac{X-\mu}{\sigma}>\dfrac{x-\mu}{\sigma})=0.10

P(z>\dfrac{x-3.2}{\sigma})=0.10\ \ \ [z=\dfrac{x-\mu}{\sigma}]

As, P(z>1.28)=0.10  [By z-table]

Then,

\dfrac{x-3.2}{0.4}=1.28\\\\\Rightarrow\ x=0.4\times1.28+3.2\\\\\Rightarrow\ x=3.712

So, it will take 3.712 hours or more to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

3 0
4 years ago
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