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2 years ago

Please help

Mathematics

1 answer:

klio [65]2 years ago

6 0

Answer:

The probability that a student taking only math will get picked is approximately 29%

Step-by-step explanation: This is because out of the total number of students taking math (95), 52 of such students are also taking science. In order to get the number of students only taking math you have to do 95-52=43 and to put that against the amount of total students the ratio would be 43:147 or 42/147 and if you plug 42/147 into a calculator you will recieve a long decimal that you can then round to 29%.

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And this one :/ I need to find what m<1=

lakkis [162]

The answer is 24° because all three the three angel of the triangle is 180° and u subtract 132 by 180 left with the other two small angel's sum which is 48. rhan u divided by two u get one of the angel which is 24°.

im pretty bad at explaining, hopefully it helps!

5 0

3 years ago

The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l

sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

$A=\frac{\sqrt{3} }{4} x^2$

(c)

$A=\frac{3\sqrt{3} }{2} x^2$

(d)

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

$=\frac{\sqrt{3} }{4} b^2$

h=3x

b=x

now, we can plug values

$A=\frac{\sqrt{3} }{4} x^2$

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

$=6\times \frac{\sqrt{3} }{4} x^2$

$=\frac{3\sqrt{3} }{2} x^2$

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

$=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)$

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

3 0

3 years ago

Read 2 more answers

Let x^2+18x=44 . What values make an equivalent number sentence after completing the square?

Lostsunrise [7]

To find the final term to compete the square you need to divide the 'x' term by 2 then square it

$x^2 +18x + = 44+ \\ x^2+18x+( \frac{18}{2} )^2=44+( \frac{18}{2} )^2 \\ x^2+18x+9^2=44+9^2 \\ x^2+18x+81=44+81 \\ (x+9)^2=125$ - equivalent equation

6 0

3 years ago

Read 2 more answers

Solve for x: 18 = x/4 + 7

alex41 [277]

jhcdfvdgfdcdgdgddgsd

4 0

3 years ago

Read 2 more answers

Solve by factoring:

DerKrebs [107]

A.<span>(x+3)(x+4)=<span>0
x=-3,-4
B.X=5,4
hope this helps
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