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bixtya [17]
3 years ago
6

HELP ILL MARK BRAINIEST

Mathematics
1 answer:
-Dominant- [34]3 years ago
4 0

Answer:

pick 3 it correct i think so or its 2

Step-by-step explanation:

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A rectangle with area
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Answer:

Step-by-step explanation

width is 9. length is 14

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3 years ago
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The table below shows the sale, in dollars, at Jacobs store over a period of five months:
lozanna [386]
The answer is B) Exponentially, shows a constant percentage in sales per month
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WHO CAN solve it Please !
Mariulka [41]

Answer:

a) True

<em>      </em>\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha  }   )d\alpha =0<em></em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given that the definite integration</em>

<em>            </em>\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha  }   )d\alpha<em></em>

<em>we know that the trigonometric formula</em>

<em> sin²∝+cos²∝ = 1</em>

<em>            cos²∝ = 1-sin²∝</em>

<u><em>step(ii):-</em></u>

<em>Now the  integration</em>

<em>         </em>\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha  }   )d\alpha = \int\limits^\pi _0 {(\sqrt{cos^{2} \alpha } } \, )d\alpha<em></em>

<em>                                      = </em>\int\limits^\pi _0 {cos\alpha } \, dx<em></em>

<em>Now, Integrating </em>

<em>                                  </em>= ( sin\alpha )_{0} ^{\pi }<em></em>

<em>                                = sin π - sin 0</em>

<em>                               = 0-0</em>

<em>                              = 0</em>

<u><em>Final answer:-</em></u>

<em>      </em>\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha  }   )d\alpha =0<em></em>

<em></em>

<em></em>

5 0
3 years ago
What is the sum of the 10th square number and the 2nd square number?
Ludmilka [50]

Answer:

104

Step-by-step explanation:

10th square number is 100, 2nd square number is 4. 100+4=104

5 0
3 years ago
Which polynomial is the product of (4x+1) and (3x+2)?
maria [59]
(4x+1)(3x+2)\\\\=4x \times 3x+4x \times 2 + 1 \times 3x + 1 \times 2\\\\ = 12x^2+8x+3x+2\\\\ = 12x^2+11x+2

Answer A
8 0
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