Hunter and Brian are creating a poster for a project and they need to combine two different size boards to create their project. If the total area cannot exceed 7x to the second power -6x+2 square inches and one board Is 2x to the second power -9x+8 square inches, then what must be the maximum area of the second board?
2 answers:
Answer:
5x² + 3x - 6
Step-by-step explanation:
Data:
Area of one board: 2x² - 9x + 8 Area of the other board: f(x) The addition of the area of the two boards cannot exceed the total area. Then:
f(x) + 2x² - 9x + 8 ≤ 7x² - 6x + 2
f(x) ≤ 7x² - 6x + 2 - 2x² + 9x - 8
f(x) ≤ (7x² - 2x²) + (-6x + 9x) + (2 - 8)
f(x) ≤ 5x² + 3x - 6 in square inches
Answer:
<em>The maximum area of the second board must be square inches. </em>
Step-by-step explanation:
The total area of two different size boards cannot exceed square inches.
The area of one board is square inches.
Suppose, the area of the second board is square inches.
That means......
So, the maximum area of the second board must be square inches.
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Step-by-step explanation: