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PSYCHO15rus [73]
2 years ago
12

Enter an expression equivalent to (3x^2+2y^2-3x) + (2x^2+y^2-2x) - (x^2 + 3y^2 +x)

Mathematics
1 answer:
11111nata11111 [884]2 years ago
4 0

Answer:

4x² - 6x

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

Distributive Property

<u>Algebra I</u>

  • Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

(3x² + 2y² - 3x) + (2x² + y² - 2x) - (x² + 3y² + x)

<u>Step 2: Simplify</u>

  1. [Distributive Property] Distribute negative:                                                    3x² + 2y² - 3x + 2x² + y² - 2x - x² - 3y² - x
  2. Combine like terms (x²):                                                                                   4x² + 2y² - 3x + y² - 2x - 3y² - x
  3. Combine like terms (y²):                                                                                   4x² - 3x - 2x - x
  4. Combine like terms (x):                                                                                    4x² - 6x
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Answer:

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Step-by-step explanation:

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3 years ago
I need help with this question.
ahrayia [7]

Answer:

59

Step-by-step explanation:

We know that all the angles must add up to 180

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8 0
2 years ago
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You buy 1.75 pounds of apples and 2.05 pounds of oranges. Apples and oranges sell for the same price per pound. The total​ cost,
dlinn [17]

Answer:

1.75c+2.05c=4.18\\\\Per\ pound\ cost=c=\$1.1

Step-by-step explanation:

Cost\ of\ per\ pound\ apple=Cost\ of\ per\ pound\ oranger=c\\\\

Cost of Apples:

Amount\ of\ apples=1.75\ pounds\\\\Cost\ of\ apples=Amount\times per\ pound\ cost\\\\Cost\ of\ apples=1.75\times c\\\\Cost\ of\ apples=1.75c

Cost of oranges:

Amount\ of\ oranges=2.05\ pounds\\\\Cost\ of\ oranges=Amount\times per\ pound\ cost\\\\Cost\ of\ oranges=2.05\times c\\\\Cost\ of\ oranges=2.05c

Total cost:

Total\ cost\ of\ fruits=cost\ of\ apple+cost\ of\ oranges\\\\Total\ cost\ of\ fruits=1.75c+2.05c\\\\After\ coupon\ cost=\$ 3.43\\\\ Original\ cost=After\ coupon\ cost+coupon\ amount\\\\ Original\ cost=3.43+0.75=4.18

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4 0
3 years ago
the diameters of Douglas firs grown at a Christmas tree farm are normally distributed with a mean of 4 inches and a standard dev
aksik [14]

Answer:

Proportion of the trees will have diameters between 2 and 6 inches = 0.8164

Step-by-step explanation:

Given -

Mean (\nu )  = 4

Standard deviation (\sigma  ) = 1.5

Let X be the diameter of tree

proportion of the trees will have diameters between 2 and 6 inches =

P(2<  X<  6)   =  P(\frac{2 - 4 }{1.5}< \frac{X - \nu }{\sigma}<  \frac{6 - 4 }{1.5})

                         = P(\frac{-2 }{1.5}< Z<  \frac{2 }{1.5})     Put  [Z = \frac{X - \nu }{\sigma}]

                         =  P(-1.33< Z<  1.33)

                          = (Z<  1.33) - (Z<  -1.33)

                          = .9082 - .0918

                           = 0.8164

6 0
3 years ago
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