Answer:
A. v = 19√3.
B. u = 38.
Step-by-step explanation:
The following data were obtained from the question:
Angle θ = 60°
Adjacent = 19
Opposite = v
Hypothenus = u
A. Determination of the value of 'v'
The value of v can be obtained by using Tan ratio as shown below:
Angle θ = 60°
Adjacent = 19
Opposite = v
Tan θ = Opposite /Adjacent
Tan 60 = v/19
Cross multiply
v = 19 × Tan 60
Tan 60 = √3
v = 19 × √3
v = 19√3
Therefore, the value of v is 19√3
B. Determination of the value of 'u'
The value of u can be obtained by using cosine ratio as shown below:
Angle θ = 60°
Adjacent = 19
Hypothenus = u
Cos θ = Adjacent /Hypothenus
Cos 60 = 19/u
Cos 60 = 1/2
1/2 = 19/u
Cross multiply
u = 2 × 19
u = 38
Therefore, the value of u is 38.
A: l x w = a formula for area
l = w + 48 length
w(w+48) = 3024 substitute l with w+48
w^2 + 48w -3024=0 —solution to part A
B: w^2 + 48w - 3024 = 0 factor
(w-36)(w+84) = 0
Solutions for width = 36,-84
A width can’t be negative, so the width is 36 inches
Answer:
The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:
The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:
The information provided is:
<em>σ</em> = $60
<em>MOE</em> = $2
The critical value of <em>z</em> for 95% confidence level is:
Compute the sample size as follows:
![n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csigma%20%7D%7BMOE%7D%5D%5E%7B2%7D)
![=[\frac{1.96\times 60}{2}]^{2}](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1.96%5Ctimes%2060%7D%7B2%7D%5D%5E%7B2%7D)
Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
Step-by-step explanation:
8×20×50×125=1000000.....
Answer
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