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2 years ago

How can I tell if f(x)=400 in f(x)=4x-9 or if t(n)=400 in t(n)=4n-9?

Mathematics

1 answer:

yKpoI14uk [10]2 years ago

7 0

Use the graph on your calculator and then check their roots and their vertex

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BRAINLIESTTT ASAP! PLEASE HELP ME :)

11Alexandr11 [23.1K]

<h3>Answer: B) Only the first equation is an identity</h3>

========================

I'm using x in place of theta. For each equation, I'm only altering the left hand side.

Part 1

cos(270+x) = sin(x)

cos(270)cos(x) - sin(270)sin(x) = sin(x)

0*cos(x) - (-1)*sin(x) = sin(x)

0 + sin(x) = sin(x)

sin(x) = sin(x) ... equation is true

Identity is confirmed

---------------------------------

Part 2

sin(270+x) = -sin(x)

sin(270)cos(x) + cos(270)sin(x) = -sin(x)

-1*cos(x) + 0*sin(x) = -sin(x)

-cos(x) = -sin(x)

We don't have an identity. If the right hand side was -cos(x), instead of -sin(x), then we would have an identity.

7 0

2 years ago

Laura created a website to create T-shirts. In the first month she put up her website she had only a single T-shirt order. Each

kiruha [24]

Laura received 144 orders over the first year

Solution:

Given function is:

f(n) = 2n - 1

Where, "n" is the month

In the first month she put up her website she had only a single T-shirt order

f(1) = 2(1) - 1 = 2 - 1

f(1) = 1

There are 12 months in a year

For the second month, and third month and so on, substitute n = 2, 3 and so on

f(2) = 2(2) - 1 = 4 - 1 = 3

f(3) = 2(3) - 1 = 6 - 1 = 5

f(4) = 2(4) - 1 = 8 - 1 = 7

f(5) = 2(5) - 1 = 10 - 1 = 9

f(6) = 2(6) - 1 = 12 - 1 = 11

f(7) = 2(7) - 1 = 14 - 1 = 13

f(8) = 2(8) - 1 = 16 - 1 = 15

f(9) = 2(9) - 1 = 18 - 1 = 17

f(10) = 2(10) - 1 = 20 - 1 = 19

f(11) = 2(11) - 1 = 22 - 1 = 21

f(12) = 2(12) - 1 = 24 - 1 = 23

Thus total orders received over first year:

Total orders = 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23

Total orders = 144

Thus she received 144 orders over the first year

8 0

2 years ago

Find the derivative of ln(cosx²).

RoseWind [281]

Answer:

$\displaystyle \frac{dy}{dx} = -2x \tan (x^2)$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle y = \ln (\cos x^2)$

Step 2: Differentiate

Logarithmic Differentiation [Derivative Rule - Chain Rule]: $\displaystyle y' = \frac{(\cos x^2)'}{\cos x^2}$
Trigonometric Differentiation [Derivative Rule - Chain Rule]: $\displaystyle y' = \frac{-\sin x^2 (x^2)'}{\cos x^2}$
Basic Power Rule: $\displaystyle y' = \frac{-2x \sin x^2}{\cos x^2}$
Rewrite [Trigonometric Identities]: $\displaystyle y' = -2x \tan (x^2)$