A fair number cube has faces numbered from 1 to 6. When the number cube is rolled, the theoretical probability of it landing on
2 answers:
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Having obtained:
the next thing to do is collect the first three terms and write them as the square of a binomial, and also collect the last two terms, writing each of them with a denominator equal to 4a^2
We have:
.
Then, we take
to the right side and write these two terms as one:
.
Next, we take the square root of both sides, which has been shown in the solution.
Next, we have to take b/2a to the right hand side as -(b/2a), and removing the square in the denominator of the right hand side expression:
.
Answer: the steps to complete in the boxes are :
.
.
.
the next thing to do is collect the first three terms and write them as the square of a binomial, and also collect the last two terms, writing each of them with a denominator equal to 4a^2
We have:
Then, we take
Next, we take the square root of both sides, which has been shown in the solution.
Next, we have to take b/2a to the right hand side as -(b/2a), and removing the square in the denominator of the right hand side expression:
Answer: the steps to complete in the boxes are :