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Mama L [17]
3 years ago
11

J(x) = 2x²+8x-5 What is this in vertex form

Mathematics
1 answer:
pav-90 [236]3 years ago
5 0

Answer:

The vertex form parabola   y = 2( x+4)² -37    

Step-by-step explanation:

<u>Step(i):-</u>

Given parabola equation  j(x) = 2x² + 8x -5

Let    y = 2x² + 8x -5

⇒   y = 2(x² + 2(4x)+(4)²-(4)²) -5

By using  (a + b)² = a² +2ab +b²

       y = 2(x+4)²- 32 -5    

        y = 2 ( x-(-4))² -37      

<u><em>Step(ii):-</em></u>

The vertex form parabola   y = a( x-h)² +k

The vertex form parabola   y = 2(x+4)² -37    

   

                   

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Shane covered the front of the kite at the right with paper. How many square inches of paper did Shane use?
Daniel [21]

Answer: 14 in.

Step-by-step explanation:

https://studyandanswers.com/mathematics/question15147255?#

5 0
3 years ago
A candy box is made from a piece of cardboard that measures 23 by 13 inches. Squares of equal size will be cut out of each corne
wolverine [178]

Answer:

2.67 inches.

Step-by-step explanation:

Assuming that we represent the size of the squares with the letter y, such that after the squares are being cut from each corner, the rectangular length of the box that is formed can now be ( 23 - 2y), the width to be (13 - 2y) and the height be (x).

The formula for a rectangular box = L × B × W

= (23 -2y)(13-2y) (y)

= (299 - 46y - 26y + 4y²)y

= 299y - 72y² + 4y³

Now for the maximum volume:

dV/dy = 0

This implies that:

299y - 72y² + 4y³ = 299 - 144y + 12y² = 0

By using the quadratic formula; we have :

= \dfrac{-b \pm \sqrt{b^2 -4ac}}{2a}

where;

a = 12; b = -144 and c = 299

= \dfrac{-(-144) \pm \sqrt{(-144)^2 -4(12)(299)}}{2(12)}

= \dfrac{144 \pm \sqrt{20736 -14352}}{24}

= \dfrac{144 \pm \sqrt{6384}}{24}

= \dfrac{144 \pm79.90}{24}

= \dfrac{144 + 79.90}{24} \ \  OR  \ \   \dfrac{144 - 79.90}{24}

= 9.33 \ \  OR  \ \ 2.67

Since the width is 13 inches., it can't be possible for the size of the square to be cut to be 9.33

Thus, the size of the square to be cut out from each corner to obtain the maximum volume is 2.67 inches.

3 0
3 years ago
Enter a positive common factor (other than 1) of the fractions numerator and denominator
Oksi-84 [34.3K]

Answer:

they both have 5 in common

if you were to reduce the fraction it would be 11/16 because

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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What parts of the right triangle are used when applying the Pythagorean Theorem? How is it used to solve a right triangle?
Bogdan [553]
You use the equation a^2 + b^2 = c^2 and the parts include the hypotenuse which is across from the right angle(the diagonal part of the triangle) and this is also the c for the equation and the a and b are the two legs(the other lengths of the triangle) and to find one of these you plug what you know into the equation and go from there
5 0
3 years ago
(i wont ask anymore after this)
nadezda [96]

Answer:

a) v = 0

b) b = 7 / 6

c) a = any number

Step-by-step explanation:

a)    7(2+5v)=3v+14

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     35v - 3v = 14 - 14

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b) -3 (3-6b)=6b+5

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   12b = 14

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c) 2 (a-2)=2a-4

    2a - 4 = 2a - 4

    2a -4 + 4 = 2a -4 + 4

    2a = 2a

     a = a ........ a cab be any number

7 0
3 years ago
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