8+11=19 but if you add 21+19+12+5=57.
The complete version of question:
<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>
Answer:
Step-by-step explanation:
As the description of the statement is:
'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>
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As
- <em>Five times the sum of a number and 27 </em>is written as:

- <em>greater than or equal </em>is written as:

- <em>six times the sum of that number and 26' </em>is written as: 6(x + 26)
so lets combine the whole statement:
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solving
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Therefore,
Answer: The answer is B
Step-by-step explanation: 122 >7 (z+8) -5 (6+z). Then switch them, 7 (z+8) -5 (6+z) <122. Expanded: 7 (z+8) -5 (6+z) <122:v 2z+26
2z+26<122, subtract 26 from both sides: 2z+26-26<122-26
Simplify: 2z<96, divide both sides by 2: 2z over 2 < 96 over 2
and finally simplified: Z<48
HOPE THIS HELPED YOU OUT!
IF NOT SORRY!
Answer:
The rental fee is 25
Step-by-step explanation:
Total cost = rental fee plus cost per hours * number hours
t = f + 8*h where t = total cost, f = rental fee, h = hours
73 = f + 8*6
73 = f+ 48
Subtract 48 from each side
73 - 48 = f+48-48
25 = f
The rental fee is 25
The correct answer is 42.
5 • 8 = 40
40 + 2 = 42