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miss Akunina [59]
3 years ago
8

Please help :)

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
3 0
The answer is linear pair postulate hope this helps.❤️
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PLEASE HELP step by step
Katen [24]

Answer:

The length of the line segment is 10 units.

Step-by-step explanation:

Let us call the given two points: (x₁, y₁) = (2, -3) and (x₂, y₂) = (8, 5).

The distance between two points, d = $ \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2} } $

Here, $ (x_1, y_1) = (2, -3) $ and

$ (x_2, y_2) = (8, 5) $

Therefore, distance, d = $ \sqrt{(8 - 2)^2 + (5 - (-3))^2 $

$ = \sqrt{6^2 + 8^2} $

$ = \sqrt{36 + 64} $

$ = \sqrt{100} $

= 10 units.

Hence, the answer.

3 0
3 years ago
A car goes 400 miles on 10 gallons of
Olenka [21]

Answer:

A. 1200

Step-by-step explanation:

Since 10 times 3 is 30, then 400 times 3 is 1200. Hope I helped!

4 0
3 years ago
Please help need answer asp
lisabon 2012 [21]
The answer to your question is B
7 0
3 years ago
Read 2 more answers
What's an equation that the passes through (-6,4) and is parallel to y=1/2x+8
deff fn [24]
By definition, if two lines share the same gradient, they are said to be parallel. So, we know for this equation, it must have a gradient of 1/2.

Now, since the point (-6, 4) passes through the line, we know it must satisfy the equation. Since we have a gradient/slope and a point, we can use the point-gradient form:

y - y_1 = \frac{1}{2}(x - x_1), where (x_1, y_1) represents the points being passed through.

y - 4 = \frac{1}{2}(x + 6)
2y - 8 = x + 6
2y = x + 14
y = \frac{1}{2}x + 7
3 0
3 years ago
Find functions f and g such that h = g ∘ f. (note: the answer is not unique. enter your answers as a comma-separated list of fun
polet [3.4K]

It is given in the question that

h(x) = (fog)(x) = x^2 -81

And x^2 -81

can also be written as

(x^2 -40) -41

Therefore,

(fog)(x) = (x^2 -40)-41

f(g(x)) = (x^2 -40)-41

That gives,

g(x) = x^2 -40, f(x) = x-41

7 0
3 years ago
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