G(x) = (x^2-6) / 2x
<span>g( n-5) = ( [n-5]^2 -6) / 2(n-5) </span>
<span>= ( n^2 -10n +25 -6 ) / 2(n-5) or ( n^2 -10n +25 -6 ) / (2n-10) </span>
<span>Your Answer </span>
<span>I did foil first and got n^2-10n+25 </span>
<span>then did 25-6 to get 19. </span>
<span>so n^2-10n+25 is on top.////// should have been n^2 -10n +19 </span>
<span>and the bottom is 2(n-5) so I distributed the 2 and got 2n-10 </span>
<span>so n^2-10n+25 </span>
<span>2n-10 </span>
<span>= (n^2 -10n +19) / 2(n-5)</span>
Answer:
If n > 0, then n= 1
If n < 0, then n=n
If you could word this a bit differently, I might be able to help more, but this is what I'm getting from it. The way you worded it is a bit confusing.
Step-by-step explanation:
Btw The one on the upper right hand side is Right angle
I don't understand your question