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2 years ago

Answer the 3 questions PLEASE

Mathematics

1 answer:

liberstina [14]2 years ago

3 0

8. it’s skewed right
9. The spread is 21 to 100
10.the center is 80 or 81

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What is the y-intercept of y = -4/3x + 4?

Reika [66]

Hello :
the y-intercept of y = -4/3x + 4 when x=0 : y= (-4/3)(0)+4=4
Answer : A) (0, 4)

7 0

2 years ago

Simplify the rational expression. State any restrictions on the variable.

natulia [17]

Answer:

t+4, t≠8

Step-by-step explanation:

$\dfrac{t^2-4t-32}{t-8}=\dfrac{(t+4)(t-8)}{(t-8)}=t+4$

The value of t must not be one that makes the denominator zero, hence must not be 8.

8 0

3 years ago

Find the quotient of '(16t^2-4)/(8t+4)'

Marizza181 [45]

here we have to find the quotient of '(16t^2-4)/(8t+4)'

now we can write 16t^2 - 4 as (4t)^2 - (2)^2

the above expression is equal to (4t + 2)(4t - 2)

there is another expression (8t + 4)

the expression can also be written as 2(4t + 2)

now we have to divide both the expressions

by dividing both the expressions we would get (4t + 2)(4t - 2)/2(4t + 2)

therefore the quotient is (4t - 2)/2

the expression comes out to be (2t - 1)

3 0

3 years ago

2 in., 3 in., 6 in. can a triangle have sides with the given lengths

Rainbow [258]

Answer:

No because the 6+4 does not equal 36.

Step-by-step explanation:

first make the hypotenuse 6 the other two are sides A and B

Use the pythagorean theorem: 3^2+2^2+6^2

6+4=36

3 0

3 years ago

The roots of x2 − ( ) + 34 are 5 ± 3i.

Angelina_Jolie [31]

Use quadratic formula
if you had ax^2+bx+c=0, then
x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$
a=1
b=?
c=34
subsitute
$\frac{-b+/- \sqrt{b^{2}-4(1)(34)} }{2(1)}$ =5+/-3i
$\frac{-b+/- \sqrt{b^{2}-136} }{2}$ =5+/-3i
make 5+/-3 into fraction over 2,(10+/-6i)/2
$\frac{-b+/- \sqrt{b^{2}-136} }{2}$ =(10+/-6i)/2
multiply both sides by 2
$-b+/- \sqrt{b^{2}-136}$ =10+/-6i
we conclude that -b=10
b=-10

ok so equaton is
x^2-10x+34

5 0

3 years ago

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