PLEASE HELP AND HURRY (answer the first page)
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To find the gradient of tangent to a curve at a point we take the first derivative and then substitute the coordinates of the point in.
So this tells us the tangent has gradient 6. Now we know the function so we can work out the coordinates when x=3 since f(3) = 3²=9.
The tangent is a straight line with gradient 6 passing through (3,9) so