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Anon25 [30]
3 years ago
7

muscle max gym charges a $30 fee to join plus $2 each day that you go workout. Capital cross-fit charges $10 to join and $4 each

day you use the gym. After how many days of workouts would the two gyms have cost you the same amount of money?
Mathematics
2 answers:
Ann [662]3 years ago
4 0

Answer:

5 workouts should be performed to equalize the costs between both gyms.

Step-by-step explanation:

Ivenika [448]3 years ago
3 0

Set up equations for each gym.

multiply daily cost by number of days(x) and add the fee:

Muscle max: 2x + 30

Capital: 4x + 10

Now set them

Equal to each other and solve for x:

2x + 30 = 4x + 10

Subtract 2x from both sides :

30 = 2x + 10

Subtract 10 from both sides :

20 = 2x

Divide both sides by 2:

X = 10

It will take 10 days

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AreA of a circle pls help​
Oksi-84 [34.3K]

Answer:

28.26in^{2}

Step-by-step explanation:

Given,

Radius of the circle = 3in.

Area = ?

They have told us to use 3.14 for \pi

Area formula = \pi r^{2}

=> 3.14 * 3 * 3

=> 3.14 * 9

=> 28.26in^{2}

Therefore the area of the circle is  28.26in^{2}

Hope it helps :)

4 0
3 years ago
Read 2 more answers
A patient received 250mg of a drug at noon, 6 pm, and midnight. The half-life of the drug is 6 hours. Fill in the table below to
lora16 [44]

125 amount remaining Plus 250 mg dose plus 250 mg dose=625 Mg. i am correct or not reply.

5 0
3 years ago
Which statement best describes the product of 4/5 x 10?
Licemer1 [7]

Answer:

Step-by-step explanation:

4/5 x 10/1= 40/5

40 divided by 5 equals 8

The answer is 8

6 0
3 years ago
(4/9)-¹ ?????????? what is it? <br> -9/4<br> -4/9<br> 9/4
Elis [28]
Im not sure on the syntax here, but i assume the question is (4/9)^-1

(4/9)^-1
= (4^-1)/(9^-1)

A negative power is an inverse of the positive power
i.e. x^-2 = 1/x^2
This is because if we have say x^3/x^5 we simplify it by cancelling x^3 which gives 1/x^2.
Another way to think of it is to subtract the power of the bottom x from the power of the top x: 3-5 = -2 so x^3/x^5 = x^-2.
I hope this explains how negitive powers are the inverse of the positive power.

So....
(4^-1)/(9^-1)
= 9/4
Because the inverse of 4 is 1/4 and the inverse of 1/9 is 9
8 0
4 years ago
Figure 6 shows a semicircle PTS with center O and radius 8cm. QST is a sector of a circle with center S and R is the midpoint of
sveticcg [70]

(a) <TOR=pi/3 radians

To determine <TOR we use the fact that in the right-angled triangle ORT we know two sides:

|OT|=radius=8cm and |OR|=radius/2=4cm

and can use the sine:

\sin \angle OTR=\frac{r/2}{r}=\frac{1}{2}\implies \angle OTR =\frac{\pi}{6}

and since <TRO=pi/2, it must be that

\angle TOR =\pi-\frac{\pi}{2}-\frac{\pi}{6}=\frac{\pi}{3}

(b) The arc length is approximately 7.255 cm

In order to calculate the arc length QT, we need to first determine the length |ST| and the angle <OST.

Towards determining angle <OST:

\angle SOT = \pi - \angle TOR = \pi - \frac{\pi}{3} = \frac{2}{3}\pi

Next, draw a line connecting P and T. Realize that triangle PTS is right-angled with <PTS=pi/2. This follows from the Thales theorem. Since R is a midpoint between P and O, it follows that the triangles ORT and PRT are congruent. So the angles <PTR and <OTR are congruent. Knowing <PTS we can  determine angle <OTS:

\angle OTR \cong \angle PTR=\frac{\pi}{6}\implies\angle OTS=\angle PTS -\angle PTR -\angle OTR\\\angle OTS = \frac{\pi}{2}-\frac{\pi}{6}-\frac{\pi}{6}=\frac{\pi}{6}

and so the angle <OST is

\angle OST = \pi - \angle TOS - \angle OTS = \pi -\frac{2}{3}\pi - \frac{1}{6}\pi=\frac{\pi}{6}

Towards determining |TS|:

Use cosine:

\cos \angle OST =\frac{|RS|}{|ST|}\implies |ST|=\frac{\frac{3}{2}r}{\cos \frac{\pi}{6}}=\frac{12\cdot 2}{\sqrt{3}}=8\sqrt{3}cm

Finally, we can determine the arc length QT:

QT = {\angle OST}\cdot |ST|=\frac{\pi}{6}\cdot 8 \sqrt{3}=\frac{4\pi}{\sqrt{3}}\approx 7.255cm




3 0
3 years ago
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