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Anon25 [30]
3 years ago
7

muscle max gym charges a $30 fee to join plus $2 each day that you go workout. Capital cross-fit charges $10 to join and $4 each

day you use the gym. After how many days of workouts would the two gyms have cost you the same amount of money?
Mathematics
2 answers:
Ann [662]3 years ago
4 0

Answer:

5 workouts should be performed to equalize the costs between both gyms.

Step-by-step explanation:

Ivenika [448]3 years ago
3 0

Set up equations for each gym.

multiply daily cost by number of days(x) and add the fee:

Muscle max: 2x + 30

Capital: 4x + 10

Now set them

Equal to each other and solve for x:

2x + 30 = 4x + 10

Subtract 2x from both sides :

30 = 2x + 10

Subtract 10 from both sides :

20 = 2x

Divide both sides by 2:

X = 10

It will take 10 days

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What is the circumference of earth's equator?
AlekseyPX

Answer:

40,075 kilometers

Step-by-step explanation:

The distance around the Earth at the Equator, its circumference, is 40,075 kilometers

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3 years ago
5-2+12÷4<br> use the order of operations
alisha [4.7K]

Step-by-step explanation:

= 5- 2 + 12 /4

= 5 -2 + 3

= 8- 2

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6 0
3 years ago
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After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modelled by the function C(t)=8(e
Alexxx [7]

Answer:

the maximum concentration of the antibiotic during the first 12 hours is 1.185 \mu g/mL at t= 2 hours.

Step-by-step explanation:

We are given the following information:

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modeled by the function where the time t is measured in hours and C is measured in \mu g/mL

C(t) = 8(e^{(-0.4t)}-e^{(-0.6t)})

Thus, we are given the time interval [0,12] for t.

  • We can apply the first derivative test, to know the absolute maximum value because we have a closed interval for t.
  • The first derivative test focusing on a particular point. If the function switches or changes from increasing to decreasing at the point, then the function will achieve a highest value at that point.

First, we differentiate C(t) with respect to t, to get,

\frac{d(C(t))}{dt} = 8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)})

Equating the first derivative to zero, we get,

\frac{d(C(t))}{dt} = 0\\\\8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0

Solving, we get,

8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0\\\displaystyle\frac{e^{-0.4}}{e^{-0.6}} = \frac{0.6}{0.4}\\\\e^{0.2t} = 1.5\\\\t = \frac{ln(1.5)}{0.2}\\\\t \approx 2

At t = 0

C(0) = 8(e^{(0)}-e^{(0)}) = 0

At t = 2

C(2) = 8(e^{(-0.8)}-e^{(-1.2)}) = 1.185

At t = 12

C(12) = 8(e^{(-4.8)}-e^{(-7.2)}) = 0.059

Thus, the maximum concentration of the antibiotic during the first 12 hours is 1.185 \mu g/mL at t= 2 hours.

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2 years ago
2(x + 4) + 2x + 3 = 3x + 16<br>what does x eqaul​
Ad libitum [116K]

Answer:

x=5

Step-by-step explanation:

2(x+4)+2x+3=3x+16

One solution was found :

                  x = 5

7 0
3 years ago
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