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Svetlanka [38]
3 years ago
11

Hi can you help me please?)

Mathematics
1 answer:
AlladinOne [14]3 years ago
5 0

<em>*To solve for a specified variable, you need to isolate that variable onto one side.</em>

<h3>11.</h3>

Firstly, subtract 5r on both sides: 2p=q-5r

Lastly, divide both sides by 2 and <u>your answer will be p=\frac{1}{2}q-\frac{5}{2}r</u>

<h3>12.</h3>

First, subtract z on both sides of the equation: -10-z=xy

Next, divide both sides by y and <u>your answer will be \frac{-10-z}{y}=x</u>

<h3>13.</h3>

Firstly, multiply both sides by b: a=cb

Next, divide both sides by c and <u>your answer will be \frac{a}{c}=b</u>

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18 divided by 2 equals 9 because
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Answer:

anwer a

2 times 9 equals to 18

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3 years ago
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On a map, 2 cm represents 30 mi. The actual distance between two towns
nydimaria [60]

Answer:

<h2>5 cm</h2>

Step-by-step explanation:

step one:

Given that the scale of the map is

 2cm to represent 30 miles

That is  every 1 cm is 15 miles in reality

step one:

what we are solving for is the distance in cm on the map so,

1cm rep 15miles

xcm rep 75miles

cross multiply

Xcm= 75/15

X= 5 cm

hence on the map 75miles distance between the two towns is seen as 5 cm

8 0
3 years ago
Find the surface area:
ANTONII [103]

Answer:

120 in

Step-by-step explanation:

(5 in * 12 in)/2 = 30 in

30 in * 4 = 120 in

I hope that helps :D

8 0
3 years ago
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Determine the quotient of 2/3 divided by 4 using a visual model. Show me how..,
azamat
4 divided by 2/3 equals 6. And 2/3 divided by 4 equals about 0.1666

First you would write it as 4/1 divided by 2/3, then you would you keep, change, flip. If you do not know how to keep,change,flip just keep the first fraction then change the division sign to multiplication then flip the last fraction. Then you should get the answer. And if you need to simplify make sure to do that.
5 0
3 years ago
If
baherus [9]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: cos 330 = \frac{\sqrt3}{2}

Use the Double-Angle Identity: cos 2A = 2 cos² A - 1

\text{Scratchwork:}\quad \bigg(\dfrac{\sqrt3 + 2}{2\sqrt2}\bigg)^2 = \dfrac{2\sqrt3 + 4}{8}

Proof LHS → RHS:

LHS                          cos 165

Double-Angle:        cos (2 · 165) = 2 cos² 165 - 1

                             ⇒ cos 330 = 2 cos² 165 - 1

                             ⇒ 2 cos² 165  = cos 330 + 1

Given:                        2 \cos^2 165  = \dfrac{\sqrt3}{2} + 1

                              \rightarrow 2 \cos^2 165  = \dfrac{\sqrt3}{2} + \dfrac{2}{2}

Divide by 2:               \cos^2 165  = \dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \bigg(\dfrac{2}{2}\bigg)\dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \dfrac{2\sqrt3+4}{8}

Square root:             \sqrt{\cos^2 165}  = \sqrt{\dfrac{4+2\sqrt3}{8}}

Scratchwork:            \cos^2 165  = \bigg(\dfrac{\sqrt3+1}{2\sqrt2}\bigg)^2

                             \rightarrow \cos 165  = \pm \dfrac{\sqrt3+1}{2\sqrt2}

             Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE

                             \rightarrow \cos 165  = - \dfrac{\sqrt3+1}{2\sqrt2}

LHS = RHS \checkmark

4 0
3 years ago
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