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Svetlanka [38]
3 years ago
11

Hi can you help me please?)

Mathematics
1 answer:
AlladinOne [14]3 years ago
5 0

<em>*To solve for a specified variable, you need to isolate that variable onto one side.</em>

<h3>11.</h3>

Firstly, subtract 5r on both sides: 2p=q-5r

Lastly, divide both sides by 2 and <u>your answer will be p=\frac{1}{2}q-\frac{5}{2}r</u>

<h3>12.</h3>

First, subtract z on both sides of the equation: -10-z=xy

Next, divide both sides by y and <u>your answer will be \frac{-10-z}{y}=x</u>

<h3>13.</h3>

Firstly, multiply both sides by b: a=cb

Next, divide both sides by c and <u>your answer will be \frac{a}{c}=b</u>

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Neporo4naja [7]
2a/5b = 6

(2a-5b)/5b could be written as: (2a/5b) -(5b/5b)

Repace by its equivalent value (6) -(1) = 5

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Find the area of the triangles and smal ler square and add them together ; and find the area of the complete square and set them equal to each other (these are known truths)
triangle: l×w /2
square: s^2
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4 (1/2ab)+c^2= (a+b)(a+b)
simplify

2ab+c^2= a^2+2ab+b^2
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c^2=a^2+b^2

tada!! it's proven :)
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