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kolezko [41]
3 years ago
12

Can someone please explain this issue to me..?

Computers and Technology
2 answers:
Airida [17]3 years ago
5 0

Answer:

try going to your settings and clear the data of the app,that might help but it if it doesn't, try deleting it and then download it again

Sholpan [36]3 years ago
5 0
I haven’t been able to ask any questions in a few days, maybe there’s something wrong with the app
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Online Book Merchants offers premium customers 1 free book with every purchase of 5 or more books and offers 2 free books with e
andrey2020 [161]

Answer:

This question has two parts, first part is about programming about a Player class and second for reading string from user and decide how many time duck string entered by user and terminate if user press goose string.

The explanation of both program (executable code) is given below in explanation section.

Explanation:

//Program 1

#include <iostream>

using namespace std;

int main()

{

 bool isPremiumCustomer;

 int nbooksPurchased;

 int totalBookPurchasedWithOffer;

// bool cutomerType;

 int freeBooks;

 cout<<"Press 1 for Premium Customer and 0 for regular Customer";

 cin>>isPremiumCustomer;

 cout<<"How many books you purchased ";

 cin>>nbooksPurchased;

 

 

switch(isPremiumCustomer)// what type of customer is  

{

case 1://if customer is premium

 if (nbooksPurchased >= 5&&nbooksPurchased<8)// purchase book greater between 5 and 8

  {

   freeBooks=1;//offer free book

   totalBookPurchasedWithOffer=nbooksPurchased+freeBooks;//total number of book including free book

   

   cout<<"You purchased total book with offer ";//show total books

   cout<<totalBookPurchasedWithOffer;

  }

   

  else if (nbooksPurchased >= 8)//if premium customer purchase more than 8 book

    {

    freeBooks=2;//offer two free book

    totalBookPurchasedWithOffer=nbooksPurchased+freeBooks;//total number of book including free book

    cout<<"You purchased total book with offer ";

    cout<<totalBookPurchasedWithOffer;//show total books

    }

  else{

   cout<<"You purchased total book with no offer ";

    cout<<nbooksPurchased;

   }

  break;

case 0:// if customer is regular customer

 if (nbooksPurchased >= 7&&nbooksPurchased<12)//and purchase book between 7 and 12

  {

   freeBooks=1;// offer 1 free book

   totalBookPurchasedWithOffer=nbooksPurchased+freeBooks;

   cout<<"You purchased total book with offer ";

   cout<<totalBookPurchasedWithOffer;

  }

   

  else if (nbooksPurchased >= 12)//if purchase 12 or more than 12 book

    {

    freeBooks=2;//offer two free book

    totalBookPurchasedWithOffer=nbooksPurchased+freeBooks;

    cout<<"You purchased total book with offer ";

    cout<<totalBookPurchasedWithOffer;

    }

 else{

  cout<<"You purchased total book with no offer ";

  cout<<nbooksPurchased;

  }

  break;

 

}

 

 

 

return 0;// terminate the program

 

}

/* program 1 has ended

and program 2 is started from here

#######################################################

*/

#include <iostream>

using namespace std;

int main()

{

string readstring;// take input string from user to enter either "goose" or "duck"

int count=0;//count the number of "duck"

while(readstring!="goose")//run loop, until user do not enter string  

{

 cout<<"Enter the string either goose or duck ";// prompt user to enter the string

 cin>> readstring;// read string from user

 if (readstring=="duck")//if string equal to "duck"

 {

  count=count+1;//count number of duck string enter by user

   

 }

}//exit/terminate the loop, if user enter the goose string

cout<< " Number of duck that were read " ;// show how many duck string entered by user

cout<<count;

return 0;// terminate the program

 

}

6 0
3 years ago
Which Creative Commons license type allows others to use and build upon work non-commercially, provided that they credit origina
Vera_Pavlovna [14]

Answer:

Creative Commons license type allows others to use and build upon work non-commercially, provided that they credit original author and maintain the same licensing is described below in detail.

Explanation:

Attribution-Non financially-ShareAlike

This permission lets others adapt, remix, and develop upon your work non-financially, as long as they charge you and license their new inventions under identical times. There are six separate license classes, scheduled from most to least licensed. the material in any mechanism or arrangement, so long as attribution is given to the originator.

8 0
3 years ago
Convert (0.255)¹⁰ into binary<br>​
nasty-shy [4]

0.01000001010001111011

Must click thanks and mark brainliest

3 0
3 years ago
Given an alphanumeric string made up of digits and lower case ASCII characters only, find the sum of all the digit characters in
lara31 [8.8K]

Answer:

C++.

Explanation:

#include <iostream>

#include <string>

using namespace std;

////////////////////////////////////////////////////////////////////////////

int sumDigits(string alphanumeric) {

   if (alphanumeric.length() == 1) {

       if ((int(alphanumeric[0]) >= 48) && (int(alphanumeric[0]) <= 57)) {

           cout<<int(alphanumeric[0]) - 48<<endl;

           return (int(alphanumeric[0]) - 48);

       }

       else

           return 0;

   }

   else {

       if ((int(alphanumeric[0]) >= 48) && (int(alphanumeric[0]) <= 57)) {

           cout<<int(alphanumeric[0]) - 48<<endl;

           return int(alphanumeric[0]) - 48 + sumDigits(alphanumeric.substr(1, alphanumeric.length()-1));

       }

       else

           return 0 + sumDigits(alphanumeric.substr(1, alphanumeric.length()-1));

   }

}

////////////////////////////////////////////////////////////////////////////

int main() {

   cout<<"Sum: "<<sumDigits("ab1c2d3e54");

   return 0;

}

3 0
3 years ago
Create a loop that will output all the numbers less than 200 that are evenly divisible (meaning remainder is zero) by both 5 and
Readme [11.4K]

Answer:

public class num7 {

   public static void main(String[] args) {

       int n =1;

       while(n<200){

           if(n%5==0 && n%7==0){

               System.out.print(n);

               System.out.print(",");

           }

           n++;

       }

   }

}

Explanation:

  • In Java programming Language
  • Create and initialize an int variable (n=1)
  • Create a while loop with the condition while (n<200)
  • Within the while loop use the modulo operator % to check for divisibility by 5 and 7
  • Print the numbers divisible by 5 and 7
4 0
3 years ago
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