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3 years ago

12

Which graphs are functional?

1 answer:

Daniel [21]3 years ago

5 0

Answer:

2 and 5

Step-by-step explanation:

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Given the function (Image below) [Algebra ll]

Irina18 [472]

X= -1 and -11
Put -1 and -11 in for x. The answer comes out 6

7 0

3 years ago

Is the given function continuous at x=1?

rusak2 [61]

Answer:

The answer is "Option C".

Step-by-step explanation:

Given:

$\to f(x)=2x^2-3x+1\\\\when \ x=1\\\\\to f(1)= 2(1)^2-3(1)+1\\\\\to f(1)= 2(1)-3+1\\\\\to f(1)= 2-3+1\\\\\to f(1)=-1+1\\\\\to f(1)=0$

That's why choice C is correct.

3 0

3 years ago

F(x)=3x graphed give answer

BaLLatris [955]

Answer:

Step-by-step explanation:

7 0

3 years ago

The indefinite integral can be found in more than one way. First use the substitution method to find the indefinite integral. Th

Fantom [35]

Answer:

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C$

Step-by-step explanation:

To find:

∫ $6x^5(x^6-2)\,dx$

Solution:

Method of substitution:

Let $x^6-2=t$

Differentiate both sides with respect to $t$

$6x^5\,dx=dt$

[use $(x^n)'=nx^{n-1}$ ]

So,

∫ $6x^5(x^6-2)\,dx$ = ∫ $t\,dt$ = $\frac{t^2}{2}+C_1$ where $C_1$ is a variable.

(Use ∫ $t^n\,dt=\frac{t^{n+1} }{n+1}$ )

Put $t=x^6-2$

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C_1$

Use $(a-b)^2=a^2+b^2-2ab$

So,

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C_1=\frac{1}{2}(x^{12}+4-4x^6)+C_1=\frac{x^{12} }{2}-2x^6+2+C_1=\frac{x^{12} }{2}-2x^6+C$

where $C=2+C_1$

Without using substitution:

∫ $6x^5(x^6-2)\,dx$ = ∫ $6x^{11}-12x^5\,dx$ = $\frac{6x^{12} }{12}-\frac{12x^6}{6}+C=\frac{x^{12} }{2}-2x^6+C$

So, same answer is obtained in both the cases.

7 0

2 years ago

Function 1 is defined by the equation p=r + 7.

MariettaO [177]

Answer:

Function 2

Step-by-step explanation:

Function 1 has a slope of 1.

Function 2 has a slope of 1.1.

1.1 > 1, so Function 2 has a greater slope.

4 0

3 years ago

Read 2 more answers