Which graphs are functional?

I keep trying to use the Pythagorean Theorem to find the missing sides length but it comes to a -31 then an Error when square ro

OverLord2011 [107]

Diagonal of the left triangle = ((8)^2+(7)^2)^0.5= (113)^0.5
x =( 12^2 -(113)^0.5)^2))^0.5=( 144- 113)^0.5= (31)^0.5= 5.57

For ur working, ur mistake lies in the line : x^2+12^2=10.6^2
It shld be 12^2= x^2+10.6^2

3 0

4 years ago

Read 2 more answers

-4x+9(10x-1) <br> please help me this is distributive property

kotykmax [81]

Let me walk you through this real quick:

-4x + 9 (10x - 1)
-4x + 90x - 9 (open up the brackets)
90x - 4x - 9
= 86x - 9

3 0

3 years ago

aFigures A and Figures B are shown on the coordinate grid. Which series of transformations demonstrates that the figures are con

Akimi4 [234]

Answer:

C) angles are congruent and all corresponding pairs of sides are congruent a similarity transformation alt corresponding pairs

Step-by-step explanation:

5 0

3 years ago

Find the explicit formula for the geometric sequence cn given below. Note that c1=6.

kodGreya [7K]

The explicit formula for the geometric sequence $c_{n}$ is

$c_{n}=6(\frac{-1}{3})^{n-1}$

Step-by-step explanation:

The formula of the nth term of a geometric sequence is

$a_{n}=a(r)^{n-1}$ , where:

a is the first term of the sequence
r is the common ratio between the consecutive terms

The geometric sequence of $c_{n}$ is 6 , -2 , $\frac{2}{3}$ , $\frac{-2}{9}$ , $\frac{2}{27}$

∵ $c_{1}$ = 6

∵ $r=\frac{c_{2}}{c_{1}}$

∵ $c_{2}$ = -2

∴ $r=\frac{-2}{6}$

- Divide both term by 2 to simplify it

∴ $r=\frac{-1}{3}$

∵ $c_{n}=c_{1}(r)^{n-1}$

- Substitute the value of $c_{1}$ and r in the rule above

∴ $c_{n}=6(\frac{-1}{3})^{n-1}$

The explicit formula for the geometric sequence $c_{n}$ is

$c_{n}=6(\frac{-1}{3})^{n-1}$

Learn more:

You can learn more about the geometric sequence in brainly.com/question/1522572

#LearnwithBrainly

6 0

3 years ago

7) PG & E have 12 linemen working Tuesdays in Placer County. They work in groups of 8. How many

BabaBlast [244]

Part A

Since order matters, we use the nPr permutation formula

We use n = 12 and r = 8

$_{n}P_{r} = \frac{n!}{(n-r)!}\\\\_{12}P_{8} = \frac{12!}{(12-8)!}\\\\_{12}P_{8} = \frac{12!}{4!}\\\\_{12}P_{8} = \frac{12*11*10*9*8*7*6*5*4*3*2*1}{4*3*2*1}\\\\_{12}P_{8} = \frac{479,001,600}{24}\\\\_{12}P_{8} = 19,958,400\\\\$

There are a little under 20 million different permutations.

<h3>Answer: 19,958,400</h3>

Side note: your teacher may not want you to type in the commas

============================================================

Part B

In this case, order doesn't matter. We could use the nCr combination formula like so.

$_{n}C_{r} = \frac{n!}{r!(n-r)!}\\\\_{12}C_{8} = \frac{12!}{8!(12-8)!}\\\\_{12}C_{8} = \frac{12!}{4!}\\\\_{12}C_{8} = \frac{12*11*10*9*8!}{8!*4!}\\\\_{12}C_{8} = \frac{12*11*10*9}{4!} \ \text{ ... pair of 8! terms cancel}\\\\_{12}C_{8} = \frac{12*11*10*9}{4*3*2*1}\\\\_{12}C_{8} = \frac{11880}{24}\\\\_{12}C_{8} = 495\\\\$

We have a much smaller number compared to last time because order isn't important. Consider a group of 3 people {A,B,C} and this group is identical to {C,B,A}. This idea applies to groups of any number.

-----------------

Another way we can compute the answer is to use the result from part A.

Recall that:

nCr = (nPr)/(r!)

If we know the permutation value, we simply divide by r! to get the combination value. In this case, we divide by r! = 8! = 8*7*6*5*4*3*2*1 = 40,320

So,

$_{n}C_{r} = \frac{_{n}P_{r}}{r!}\\\\_{12}C_{8} = \frac{_{12}P_{8}}{8!}\\\\_{12}C_{8} = \frac{19,958,400}{40,320}\\\\_{12}C_{8} = 495\\\\$

Not only is this shortcut fairly handy, but it's also interesting to see how the concepts of combinations and permutations connect to one another.

-----------------

<h3>Answer: 495</h3>

5 0

3 years ago