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topjm [15]
3 years ago
7

Bella says 18 is the same as 10 ones and 8 tens

Mathematics
2 answers:
ss7ja [257]3 years ago
7 0

Answer:

Bella is largely mistaken.

Step-by-step explanation:

What she described equals 90

Degger [83]3 years ago
7 0
Bella is wrong, 10 is in the ones place and 8 is the tens place.
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A study by the National Athletic Trainers Association surveyed random samples of 1679 high school freshmen and 1366 high school
nekit [7.7K]

Answer:

We conclude that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids.

Step-by-step explanation:

We are given that a study by the National Athletic Trainers Association surveyed random samples of 1679 high school freshmen and 1366 high school seniors in Illinois.

Results showed that 34 of the freshmen and 24 of the seniors had used anabolic steroids.

Let p_1 = <u><em>proportion of Illinois high school freshmen who have used anabolic steroids.</em></u>

p_2 = <u><em>proportion of Illinois high school seniors who have used anabolic steroids.</em></u>

SO, Null Hypothesis, H_0 : p_1=p_2      {means that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids}

Alternate Hypothesis, H_A : p_1\neq p_2      {means that there is a significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids}

The test statistics that would be used here <u>Two-sample z test for</u> <u>proportions</u>;

                        T.S. =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }  ~ N(0,1)

where, \hat p_1 = sample proportion of high school freshmen who have used anabolic steroids = \frac{34}{1679} = 0.0203

\hat p_2 = sample proportion of high school seniors who have used anabolic steroids = \frac{24}{1366} = 0.0176

n_1 = sample of high school freshmen = 1679

n_2 = sample of high school seniors = 1366

So, <u><em>the test statistics</em></u>  =  \frac{(0.0203-0.0176)-(0)}{\sqrt{\frac{0.0203(1-0.0203)}{1679}+\frac{0.0176(1-0.0176)}{1366} } }

                                     =  0.545

The value of z test statistics is 0.545.

Since, in the question we are not given with the level of significance so we assume it to be 5%. <u>Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.</u>

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids.

3 0
3 years ago
ASAP! 35 points! Factor the perfect square trinomial. <br> x^2−22x+121 <br><br> answer: _______
blondinia [14]

Answer:

( x − 11 ) 2

Step-by-step explanation:

4 0
3 years ago
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Point C(3.6, -0.4) divides in the ratio 3 : 2. If the coordinates of A are (-6, 5), the coordinates of point B are . If point D
polet [3.4K]
Given:
A has coordinates (-6,5)
C has coordinates (3.6,-0.4).
C divides AB in the ratio 3:2.

Refer to the diagram shown below.
The coordinates of B are determined by
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Also,
\frac{5-(-0.4)}{5-y} = \frac{3}{5} \\ 3(5-y) = 27 \\ 15-3y=27 \\ y= \frac{12}{-3} =-4

Answer:
The coordinates of B are (10,-4).

Now, we know the coordinates of line segment AB as A (-6, 5) and B (10,-4).
D (x,y) divides AB in the ratio 4:5.
Therefore
\frac{x-(-6)}{10-(-6)} = \frac{4}{4+5} \\ \frac{x+6}{16} = \frac{4}{9} \\ 9(x+6)=64 \\ 9x+54=64 \\ x=1.11
Also,
\frac{5-y}{5-(-4)} = \frac{4}{9}  \\ 5-y = 4 \\ y = 1

Answer:
The coordinates of D are (1.11, 1)

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Answer:

6?

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3 years ago
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Answer:

with what?

Step-by-step explanation:

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