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lana66690 [7]
2 years ago
12

Help please ASAP I really don’t understand

Mathematics
1 answer:
ad-work [718]2 years ago
3 0
If I’m not mistaken I really think it is the 3rd option
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13. Tom has $14 more than you do.
puteri [66]

Answer:

46

Step-by-step explanation:

14-60 equals 46 and just go to your answer and put that in and there u go buddy

8 0
3 years ago
Melanie makes $3.00 less per hour babysitting than her best friend, Carita. If the combined hourly rate of Melanie and Carita is
marysya [2.9K]

Answer:

B 6.00

Step-by-step explanation:

M= 6$

C= 9$

M+C= 6+9= 15$ per hour

3 0
3 years ago
Which of the following is the graph of (x + 3)2 + (y - 1)2 = 9? A B с 2. 2 2 2 4 -2 4 2 -2 2 2 4 2.​
Zarrin [17]

The third one is the correct graph for the equation

hope it helps !!

5 0
2 years ago
Find the integral using substitution or a formula.
Nadusha1986 [10]
\rm \int \dfrac{x^2+7}{x^2+2x+5}~dx

Derivative of the denominator:
\rm (x^2+2x+5)'=2x+2

Hmm our numerator is 2x+7. Ok this let's us know that a simple u-substitution is NOT going to work. But let's apply some clever Algebra to the numerator splitting it up into two separate fractions. Split the +7 into +2 and +5.

\rm \int \dfrac{x^2+2+5}{x^2+2x+5}~dx

and then split the fraction,

\rm \int \dfrac{x^2+2}{x^2+2x+5}~dx+\int\dfrac{5}{x^2+2x+5}~dx

Based on our previous test, we know that a simple substitution will work for the first integral: \rm \quad u=x^2+2x+5\qquad\to\qquad du=2x+2~dx

So the first integral changes,

\rm \int \dfrac{1}{u}~du+\int\dfrac{5}{x^2+2x+5}~dx

integrating to a log,

\rm ln|x^2+2x+5|+\int\dfrac{5}{x^2+2x+5}~dx

Other one is a little tricky. We'll need to complete the square on the denominator. After that it will look very similar to our arctangent integral so perhaps we can just match it up to the identity.

\rm x^2+2x+5=(x^2+2x+1)+4=(x+1)^2+2^2

So we have this going on,

\rm ln|x^2+2x+5|+\int\dfrac{5}{(x+1)^2+2^2}~dx

Let's factor the 5 out of the intergral,
and the 4 from the denominator,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\frac{(x+1)^2}{2^2}+1}~dx

Bringing all that stuff together as a single square,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(\dfrac{x+1}{2}\right)^2+1}~dx

Making the substitution: \rm \quad u=\dfrac{x+1}{2}\qquad\to\qquad 2du=dx

giving us,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(u\right)^2+1}~2du

simplying a lil bit,

\rm ln|x^2+2x+5|+\frac52\int\dfrac{1}{u^2+1}~du

and hopefully from this point you recognize your arctangent integral,

\rm ln|x^2+2x+5|+\frac52arctan(u)

undo your substitution as a final step,
and include a constant of integration,

\rm ln|x^2+2x+5|+\frac52arctan\left(\frac{x+1}{2}\right)+c

Hope that helps!
Lemme know if any steps were too confusing.

8 0
3 years ago
Darcy, Jason, and Maria share $268. Jason has $20 more then Darcy
aleksandr82 [10.1K]

Answer:

Darcy and Jason have $124 combined

Step-by-step explanation:

8 0
3 years ago
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