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3 years ago

5

((((((ASAP))))))On Tuesday afternoon at camp, Finn did archery and sailing before dinner. Archery started at 12:10 P.M. Finn spe

nt 1 hour and 25 minutes at archery and 40 minutes sailing. What time did sailing end?
Include A.M. or P.M. in your answer (for example, 11:58 A.M.).

2 answers:

Andrei [34K]3 years ago

3 0

Answer:

2:15

Step-by-step explanation:

legit just mush it up and add or sum .-.

Elza [17]3 years ago

3 0

2:00 P.M i think sorry if it’s wrong I did the math in my head!

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A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of

Ivenika [448]

The equation for the height of the rocket at time t given

$h= -16t^2+192t$

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

$h= -16t^2+192t$

$560 = -16t^2+192t$

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

$560 = -16(t^2 - 12t)$

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

$560/-16 = -16(t^2-12t)/-16$

$-35 = t^2 -12t$

Now we will move -35 to the righ side by adding 35 to both sides.

$-35+35 = t^2-12t+35$

$0 = t^2 -12t+35$

$t^2-12t+35 = 0$

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

$t^2-12t+35 =0$

$(t-5)(t-7) =0$

So by using zero product property we will get

$t-5 =0$

$t-5+5 = 0+5$

$t=5$

Also $t-7 =0$

$t-7+7 = 0+7$

$t=7$

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

$h= -16t^2+192t$

$0= -16t^2 + 192 t$

$0 = -16(t^2-12t)$

$-16(t^2-12t) = 0$

We will move -16 to the other side by dividing it to both sides.

$-16(t^2-12t)/-16 = 0/-16$

$t^2-12t = 0$

We will take out the common factor t from the left side. By taking out t we will get,

$t(t-12) = 0$

We will use zero product property now. By using that we will get,

$t = 0$

ans also $t-12 = 0$

$t-12+12 = 0+12$

$t = 12$

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

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3 years ago

Which expression shows a decimal equivalent to the fraction 13/32? Show work A. 0.41 B. 0.406 C. 0.40625 D. 0.4625

lina2011 [118]

Answer:

[C] 0.40625

Explanation:

To turn a fraction into a decimal, divide the numerator by the denominator.

13 ÷ 32 = 0.40625

Your answer is [C] 0.40625

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3 years ago

0.99 0.89 7/8 least to greatest

katovenus [111]

From least to greatest 7/8, 0.89, 0.99

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3 years ago

If the parallel sides of a trapezoid are contained by the lines and , find the equation of the line that contains the midsegment

Fittoniya [83]

Answer:

Equation of midsegment line: y = (-1/4)x + 2.

Step-by-step explanation:

If the parallel sides of a trapezoid are contained by the lines:-

y = (-1/4)x +5 and y = (-1/4)x - 1

Midsegment of any trapezoid is the line segment

1. that is parallel to pair of parallel side of trapezoid and

2. that passes through the middle of the trapezoid and cuts the other two sides into equal-half.

It means the midsegment would have same slope as the parallel lines and y-intercept would be in the middle of intercepts of parallel lines.

So y = mx + b

where m = -1/4 and b = (5 - 1)/2 = 4/2 = 2.

Hence, the equation of midsegment would be y = (-1/4)x + 2.

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3 years ago

The population of a community is known to increase at a rate proportional to the number of people present at time t. If the popu

Lady bird [3.3K]

Answer:

$P(t) = P(0)e^{0.0693t}$

Step-by-step explanation:

The population of a community is known to increase at a rate proportional to the number of people present at time t.

This means that the population growth is modeled by the following differential equation:

$\frac{dP(t)}{dt} = rP(t)$

Which has the following solution:

$P(t) = P(0)e^{rt}$

In which P(t) is the population after t years, P(0) is the initial population and r is the growth rate.

The population has doubled in 10 years

This means that $P(10) = 2P(0)$ . We use this to find r.

$P(t) = P(0)e^{rt}$

$2P(0) = P(0)e^{10r}$

$e^{10r} = 2$

$\ln{e^{10r}} = \ln{2}$

$10r = \ln{2}$

$r = \frac{\ln{2}}{10}$

$r = 0.0693$

So the equation that will estimate the population of the community in t years is:

$P(t) = P(0)e^{0.0693t}$

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3 years ago