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Ronch [10]
3 years ago
10

Janice is considering buying a new home. She wants to estimate the monthly utilities (heating and air conditioning). She figures

that the utilities are dependent on the size (square footage) of the home. She collects data on 10 homes in the neighborhood and finds a linear model to give the relationship between the size of the home and the monthly utilities. The equation of the line is ŷ = –8.1 + 1.91x, where ŷ is the mean monthly cost in utilities and x is the square footage of the home. The residual plot is shown.
Based on the residual plot, is the linear model appropriate?


No, there is no clear pattern in the residual plot.

Yes, there is no clear pattern in the residual plot.

No, there are no homes between 2,300 and 2,900 square feet.

Yes, half of the residuals are positive and half are negative.


I think its (A), can someone confirm?

Mathematics
1 answer:
Maslowich3 years ago
4 0

Answer:

Pretty sure its (D). Yes, half of the residuals are positive and half are negative.

Yes, I am verifying my own answers for people who don't like to be trolled.

A is wrong, I put it in wrong the first time. D also makes sense now that I look at it more. I got an 88%

ED2021

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4.5(4 − ) + 36 = 202 − 2.5(3 + 28)<br><br>Step by Step please
PolarNik [594]

Ok so first off you need to get rid of the clauses in the equation.

So 4.5 ( -4) becomes -18 and -2.5(3+28) becomes -77.5

-18 + 36 = 202 - 77.5

Now you are going to solve the equation.

18 = 122.5

Hope this helped ;),

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3 0
3 years ago
A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)
Maksim231197 [3]

Answer:

a

  The 95% confidence interval is  0.0503  <   p < 0.1297

b

The sample proportion is  \r p =  0.09

c

The critical value is  Z_{\frac{\alpha }{2} } =  1.96

d

 The standard error is  SE   =0.020

Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  200

     The number of defective is  k =  18

The null hypothesis is  H_o  :  p  =  0.08

The  alternative hypothesis is  H_a  :  p > 0.08

Generally the sample proportion is mathematically evaluated as

            \r p =  \frac{18}{200}

            \r p =  0.09

Given that the confidence level is  95% then the level  of significance is mathematically evaluated as

        \alpha  =  100 -  95

        \alpha  =  5\%

        \alpha  =  0.05

Next we obtain the critical value of  \frac{ \alpha }{2} from the normal distribution table, the value is  

        Z_{\frac{\alpha }{2} } =  1.96

Generally the standard of error is mathematically represented as

          SE   =  \sqrt{\frac{\r p (1 -  \r p)}{n} }

substituting values

         SE   =  \sqrt{\frac{0.09  (1 -  0.09)}{200} }

        SE   =0.020

The  margin of error is  

       E =  Z_{\frac{ \alpha }{2} }  * SE

=>    E =  1.96  *  0.020

=>   E =  0.0397

The  95% confidence interval is mathematically represented as

     \r p  -  E  <  \mu <  p <  \r p  + E

=>   0.09 - 0.0397  <  \mu <  p < 0.09 + 0.0397

=>  0.0503  <   p < 0.1297

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Step-by-step explanation:

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