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ozzi
3 years ago
11

Could you guys please help with this question :) At a teacher's college, 70% of students are female. On average 75% of females a

nd 85% of males students graduate. A student who graduates is selected at random, find the probability that the student is male.
Mathematics
1 answer:
svp [43]3 years ago
5 0

Answer:

Step-by-step explanation:

70% of students are female

70/100* 75%= you get your answer

then subtract the percentage of the males and the females and then you get your answer

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30 Points!!! Please Help (Surface Area)
Nostrana [21]
Multiply base x height then divide by 2 if finding surface are if finding volume multiple base x height x width and divide by 3
4 0
2 years ago
-4x + 7 is greater than or equal to 83<br> (sorry, i couldn't get the sign for it)
bezimeni [28]

Answer:

-19

Step-by-step explanation:

you first substract 7 from 83 since its the inverse operation

then you divide it by -4 which give you -19

4 0
2 years ago
Someone help pls I forgot how to do it
yawa3891 [41]

(2,4)

Step-by-step explanation:

I'm not sure in the slightest but with the formula I learned I think this is correct

3 0
2 years ago
A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The
AURORKA [14]

Answer:

(−0.103371 ; 0.063371) ;

No ;

( -0.0463642, 0.0063642)

Step-by-step explanation:

Shift 1:

Sample size, n1 = 30

Mean, m1 = 10.53 mm ; Standard deviation, s1 = 0.14mm

Shift 2:

Sample size, n2 = 25

Mean, m2 = 10.55 ; Standard deviation, s2 = 0.17

Mean difference ; μ1 - μ2

Zcritical at 95% confidence interval = 1.96

Using the relation :

(m1 - m2) ± Zcritical * (s1²/n1 + s2²/n2)

(10.53-10.55) ± 1.96*sqrt(0.14^2/30 + 0.17^2/25)

Lower boundary :

-0.02 - 0.0833710 = −0.103371

Upper boundary :

-0.02 + 0.0833710 = 0.063371

(−0.103371 ; 0.063371)

B.)

We cannot conclude that gasket from shift 2 are on average wider Than gasket from shift 1, since the interval contains 0.

C.)

For sample size :

n1 = 300 ; n2 = 250

(10.53-10.55) ± 1.96*sqrt(0.14^2/300 + 0.17^2/250)

Lower boundary :

-0.02 - 0.0263642 = −0.0463642

Upper boundary :

-0.02 + 0.0263642 = 0.0063642

( -0.0463642, 0.0063642)

7 0
2 years ago
F(x) = 2x^2 – 5x; find f(3)​
Nookie1986 [14]

Answer:

f(3) = 3

Step-by-step explanation:

f(x) = 2x^2 – 5x

Let x = 3

f(3) = 2(3)^2 - 5(3)

      = 2*9 -15

      = 18-15

      =3

4 0
2 years ago
Read 2 more answers
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